Find the radius, and the approximate circumference and area of the circle below. (Use 3 for \pi)

Mathematics

1 answer:

Marina CMI [18]3 years ago

4 0

Answer:

Circ=37.704, Area= 112.112

Step-by-step explanation:

Circumference= pi *Diameter

Taking pi=3.142, Diameter=12

Circ=3.142*12=37.704

Area= pi * r^2

Area= 3.142*6*6=112.112

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Find the vertices and foci of the hyperbola with equation quantity x minus five squared divided by eighty one minus the quantity

Papessa [141]

If you notice, the positive fraction, is the one with the "x" variable in it, that simply means, the hyperbola is opening over the x-axis, so is a horizontal one, therefore

$\bf \textit{hyperbolas, horizontal traverse axis }
\\\\
\cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h\pm a, k)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}
\end{cases}\\\\
-------------------------------$

$\bf \cfrac{(x-5)^2}{81}-\cfrac{(y-1)^2}{144}=1\implies \cfrac{(x-5)^2}{9^2}-\cfrac{(y-1)^2}{12^2}=1~~
\begin{cases}
a=9\\
b=12
\end{cases}
\\\\\\
c=\sqrt{9^2+12^2}\implies c=15\\\\
-------------------------------\\\\
vertices~~(5\pm 9,1)\implies 
\begin{cases}
(14,1)\\
(-4,1)
\end{cases}~~foci~~(5\pm 15,1)\implies 
\begin{cases}
(20,1)\\
(-10,1)
\end{cases}$

3 0

3 years ago

Hello there. May somebody help me simplify this problem? It would be very kind.

marissa [1.9K]

Answer:

27 / (4x⁶y⁸)

Step-by-step explanation:

$\frac{4(3x^{2}y^{4})^{3}}{(2x^{3}y^{5})^{4}}$