Find an equation of variation in which y varies directly as x and y = 0.4 when x = 0.5. then find the value of y when x=15

An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than

Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: $H_0: \mu \leq 10$

The alternative hypothesis is: $H_1: \mu > 10$

b)

The critical value is: $t_c = 1.74$

The decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

c)

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of at most 10 pounds, that is:

$H_0: \mu \leq 10$

At the alternative hypothesis, it is tested if the mean loss is of more than 10 pounds, that is:

$H_1: \mu > 10$

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a significance level of 0.05 and 18 - 1 = 17 df.

Hence, using a calculator for the t-distribution, the critical value is: $t_c = 1.74$ .

Hence, the decision rule is:

If t < 1.74, we do not reject the null hypothesis.
If t > 1.74, we reject the null hypothesis.

Item c:

We have the standard deviation for the sample, hence the t-distribution is used. The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
s is the standard deviation of the sample.
n is the sample size.

For this problem, we have that:

$\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18$

Thus, the value of the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}$

$t = 1.41$

Since t = 1.41 < 1.74, we do not reject the null hypothesis, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0

2 years ago

The image shows the energy that can be generated from the Earth's water and the pull of the Moon's gravity.

tester [92]

Answer:

It is tidal energy, which is a renewable resource

Step-by-step explanation:

Tidal energy is is the energy produced when interaction of earth water masses and Moon's gravitational pull takes place. when moon's gravitational pull occurs on ocean water, currents and motion is produced in ocean water which leads to rise in water. when earth rotates this rise in water meets the shallow region of water near the shore and hence tide is created. This motion of rise and fall of water stores energy which is called tidal energy.

Renewal source is one which does not gets depleted and is replenished by nature. It's quantity will not get reduced with consumption.

example is sunlight : sunlight is renewable energy as everyday day this energy is produced . no matter how much it is consumed on earth for a day. Next day it will be again produced by earth.

Since, tides are regularly occurring phenomenon hence they are source of renewable tidal energy produced by them

7 0

3 years ago

7 × [(25 − 2) − (2 + 3)]

oee [108]

Answer:

126

Step-by-step explanation:

25-2=23

2+3=5

23-5=18

7*18=126