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andreyandreev [35.5K]

3 years ago

12

How much money invested at 5% compounded continuously for 3 years will yield $820

2 answers:

Elenna [48]3 years ago

6 0

X(1.05)^2=820

x=820 divided by 1.05^2 or 820/1.0025

Komok [63]3 years ago

4 0

I have that and it says GK equals 36 and GI equals 16

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Solve for a. Correct answer gets BRAINLIEST

Darina [25.2K]

Hey there!!

Equation given :

A = h ( a + b ) / 2

Multiply by 2 on both sides

2A = h ( a + b )

Divide by h on both sides

2A / h = a + b

Subtract by b on both sides

2A / h - ( b ) = a

Hence, the option ( a ) is the correct answer

Hope my answer helps!

3 0

3 years ago

What is the difference in length between a 1 1/4 inch button and a 3/8 inch button?

charle [14.2K]

1 1/4= 1*4+1 /4. Or 5/4

In order to subtract you must have same denominator. 5/4 -3/8

Multiply 5/4 times 2/2. =. 10/8. -3/8

The difference is 7/8

8 0

2 years ago

Pls help this is very easy

anastassius [24]

Answer:

20/9

Step-by-step explanation:

Alright, so by using the "keep me, change me, turn me over" method - we can easily solve this:

$\frac{8}{9}\div \frac{2}{5}\\=\frac{8}{9}\times \frac{5}{2}\\=\frac{4}{9}\times \frac{5}{1}\\=\frac{4\times \:5}{9\times \:1}\\=\frac{20}{9}$

<em>I hope I was of assistance!</em> <em><u>#SpreadTheLove <3</u></em>

4 0

3 years ago

There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl

insens350 [35]

We're told that

$P(A\cap B)=0.15$

$P(A\cup B)^C=0.06\implies P(A\cup B)=0.94$

$P(B\mid A)=P(B^C\mid A)=0.5$

where the last fact is due to the law of total probability:

$P(A)=P(A\cap B)+P(A\cap B^C)$

$\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)$

$\implies 1=P(B\mid A)+P(B^C\mid A)$

so that $B\mid A$ and $B^C\mid A$ are complementary.

By definition of conditional probability, we have

$P(B\mid A)=P(B^C\mid A)$

$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

$\implies P(A\cap B)=P(A\cap B^C)$

We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

$P(B)=P(A\cap B)+P(A^C\cap B)$

$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

8 0

3 years ago

What is the relationship between 5.34×1055.34×105 and 5.34×10−25.34×10−2 ?

storchak [24]

5+2=7 which means there will be 7 zeros so it is 10000000 times greater than

7 0

3 years ago

Read 2 more answers