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wel
4 years ago
14

Complete the two column proof

Mathematics
1 answer:
seraphim [82]4 years ago
8 0
The answer is 12 I promise
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John’s checking account had a balance of $126.79. He wrote a check for $75.10. Which expression represents one way to calculate
Svetlanka [38]

Answer:

D. $126.79 + (-$75.10)

Step-by-step explanation:

6 0
3 years ago
The boundary lines for the system of inequalities is given in the graph.
diamong [38]

Answer:

C)

region C

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

\displaystyle y ≤ -x + 2

0 ≤ 2 ☑ [We shade the portion of the graph that CONTAIN THE ORIGIN, which is the bottom portion.]

\displaystyle y ≥ 2x - 3

0 ≥ −3 ☑ [We shade the portion of the graph that CONTAINS THE ORIGIN, which is the left side.]

So, now that we got that all cleared up, we can tell that both graphs share a region where the ORIGIN IS VISIBLE. Therefore region C matches the above inequalities.

I am joyous to assist you anytime.

4 0
4 years ago
Read 2 more answers
What is the vertex form of the quadratic equation represented on the table?
sergeinik [125]

Check the picture below, so the parabola looks more or less like so, hmmm with a vertex at (-1 , -4), so, using those values from the table

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{vertex}{\stackrel{h}{-1}~~,~~\stackrel{k}{-4}}\qquad \implies y=a[x-(-1)]^2-4\implies y=a(x+1)^2-4 \\\\\\ \textit{we also know that} \begin{cases} x=2\\ y=14 \end{cases}\implies 14=a(2+1)^2-4\implies 18=9a \\\\\\ \cfrac{18}{9}=a\implies 2=a~\hspace{10em}\boxed{y=2(x+1)^2-4}

7 0
2 years ago
Drag the expressions into the boxes to correctly complete the table.
Maslowich

Answer:

Polynomial

x^4 +3x^3 -5x^2 -7x +20\\\\x^3 -2x^2 +x -12\\\\x^2 + 3x^5 -6x +12x^3

not a polynomial

4\sqrt[3]{x} -\sqrt{x} -20\\\\x^{-3}-x}^{-2}-6x^{-1}+8\\\\\frac{5}{x^3} -\frac{1}{x^2} +\frac{8}{x} -40\\\\

3 0
3 years ago
What is the surface area of a cylinder with a diameter of 8 centimeters and a height of 12 centimeters?
Lostsunrise [7]
The formula for this is A=2 \pi rh+2 \pi  r^{2}.  If the diameter is 8 the radius is 4, so filling in accordingly we have A=2 \pi (4)(12)+2 \pi (16) and A=96 \pi +32 \pi which is A=128 \pi and when you multiply in 3.14 you get that A = 401.92 or B above.
8 0
4 years ago
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