3 years ago

Chika left his house by 7.05pm and returned by 1.00pm. How long did he spend outside his house

Mathematics

1 answer:

Yakvenalex [24]3 years ago

5 0

Answer:

Step-by-step explanation:

7.05 p.m we can call it as 19.05

and 1.00 p.m means 13.00

so time from 19.05 to 24.00 is = 24.00-19.05= 4.55 hr

from 24.00 to 13.00 is = 13.00 hr

so total hr is 4.55 + 13.00= 17.55 hr

You might be interested in

The angles of traingle are in the ratio 3:7:8 find them in degrees as well as in radians

I am Lyosha [343]

30°, 70°, and 80°.
It is an acute-angled triangle.
Explanation:
The ratio of the measures of ∠s in Δ is 3:7:8.
So, let us suppose that the measures are, 3k, 7k, 8k.
Evidently, their sum is
180°.

3k+7k+8k=180
18k=180
k= 10

Hence, the measures are,
30°, 70°, and 80°.
As all the angles are acute, so is the triangle.

6 0

3 years ago

Which expression represents a factorization of 63 − 18?\

Evgesh-ka [11]

Answer:

Step-by-step explanation:

5+5=20

7 x 1 =78

78=9090

90900-5967=5676

harry should end with 5 tomatoes

4 0

3 years ago

How many more stickers does maddie's have on her notebook than on meg's note book

Ksivusya [100]

Depends on how many stickers each girl has.

6 0

3 years ago

Add or subtract. Simplify your answer. x+2/x^2−100 + 8/x^2−100

stiv31 [10]

$\dfrac{x+2}{x^2-100}+\dfrac{8}{x^2-100}=\dfrac{x+2+8}{x^2-100}=\dfrac{x+10}{x^2-10^2}\\\\=\dfrac{x+10}{(x+10)(x-10)}=\dfrac{1}{x-10}\to\fbox{B.}\\\\\\The\ domain:\\D:m\neq0\ and\ m\neq-7\\\\\dfrac{1}{m}=\dfrac{2}{m+7}\ \ \ \ |cross\ multiply\\\\2\cdot m=1\cdot(m+7)\\2m=m+7\ \ \ \ |subtract\ "m"\ from\ both\ sides\\\boxed{m=7}$

8 0

3 years ago

Hellpp and thanks!!

kherson [118]

Answer:

c = 4n

Step-by-step explanation:

5 0

3 years ago

Chika left his house by 7.05pm and returned by 1.00pm. How long did he spend outside his house​

Chika left his house by 7.05pm and returned by 1.00pm. How long did he spend outside his house