You have 10 marbles (5 blue, 3 white, 2 yellow) what is the probability of choosing yellow?

What's the answer for this question please thank you :)

vova2212 [387]

Answer:

Arc AB = 110

Step-by-step explanation:

<C = 55 degrees. That's the way the triangle is marked. AB = BC.

The central angle is twice the angle made by the end points of line AB

The central angle = 2*55 = 110

The measure of arc AB equals the central angle which makes arc AB = 110

7 0

3 years ago

Two cars are traveling towards a hotel on the same road. From the edge of the hotel, 600 feet high, Spiderman sits on the roofto

d1i1m1o1n [39]

Answer:

The distance between two cars is 110.64 feet.

Step-by-step explanation:

Angle of depression is defined as an angle between the line of sight and the horizontal.

Remember in a right angled triangle, the angle of depression is always same as the angle of elevation.

If $\theta$ be the angle of depression then,

$tan\theta=\frac{opposite}{adjacent}$

Given that,

Two car are travelling toward a hotel on the same road.

The height of the given building is 600 feet.

For the first car:

The angle of depression = The angle of elevation = 52°

Let the horizontal distance between the building and the car be x.

Here, $\theta =52 ^\circ$ , opposite = 600 feet, adjacent = x

$tan 52^\circ=\frac{600}{x}$

$\Rightarrow x=\frac{600}{tan 52^\circ}$

$\Rightarrow x\approx 468.77$ feet

For the second car:

The angle of depression = The angle of elevation = 46°

Let the horizontal distance between the building and the car be y.

Here, $\theta =46 ^\circ$ , opposite = 600 feet, adjacent = y

$tan 46^\circ=\frac{600}{y}$

$\Rightarrow y=\frac{600}{tan 46^\circ}$

$\Rightarrow x\approx 579.41$ feet

The distance between two cars is

= The distance of the second car from the building - The distance of the first car from the building

=(579.41-468.77) feet

=110.64 feet.

3 0

3 years ago

What is the area of the polygon given below?

labwork [276]

<h2>ANSWER:</h2>

B. 525 square units

<h2>SOLUTION:</h2>

S= 27+14+9×14+3×7

S= 525

 ${{hope it helps}}}$ 

5 0

2 years ago

Read 2 more answers

Given below are the coordinates of the vertices of a triangle. Find the lengths of the sides of the triangle, then click to iden

Shkiper50 [21]

To find the length of the sides, we use the Pythagorean Theorem. First, let's look at the side RS. R is at (1,3), and S is at (3,1). Therefore, to find RS, we use the difference in height and length: $a = \sqrt{ {b}^{2} + {c}^{2} } \\ a = \sqrt{ {(3 - 1)}^{2} + {(1 - 3)}^{2} } \\ a = \sqrt{ {(2)}^{2} + {( - 2)}^{2} } \\ a = \sqrt{4 + 4} \\ a = \sqrt{8}$
The length of side RS is square root 8.

Side ST is made from point S (3,1) and point T (5,2).
$a = \sqrt{ {(5 - 3)}^{2} + {(2 - 1)}^{2} } \\ a = \sqrt{ {(2)}^{2} + {(1)}^{2} } \\ a = \sqrt{4 + 1} \\ a = \sqrt{5}$
The length of side ST is root 5.

Side RT is between R (1,3) and T (5,2).
$a = \sqrt{ {(1 - 5)}^{2} + {(3 - 2)}^{2} } \\ a = \sqrt{ {( - 4)}^{2} + {(1)}^{2} } \\ a = \sqrt{16 + 1} \\ a = \sqrt{17}$
The side RT is root 17. The triangle is scalene, meaning it has three sides of different lengths.

4 0

2 years ago

The box plots represent the distances run by the players in a football match.

Monica [59]

Answer:

Following are the response to the given question:

Step-by-step explanation:

Its scope, as well as the cross median range, could be established using the measurement for dispersal by looking at even a booth map. We simply search for the difference between the larger and lowest data value to define the range, and we make all the difference between the third quartile and first quarter for the disposing of products and services ranges.

Team A:

$R=V_{max} -V_{min} \to R= 10.2 – 8.8 = 1.4 \\\\IQR = Q_3 - Q_1 = IQR = 9.09 - 9.5 = 0.4\\\\$

Team B:

$R= 10.4 - 9.0 = 1.4\\\\IQR= 10.1 – 9.6 = 0.5$

Based on previous results, you see an equal range, but variation in the interquartile. Group B does have a greater confidence interval than Group A, therefore we can say it is far more consistent over group B distance. Group A is a different type.

7 0

2 years ago