Answer:
(c) For p = 15, 
leaves a remainder of -2 when divided by (x-3).
Step-by-step explanation:
Here, The dividend expression is = E(x)
The Divisor = (x-3)
Remainder = -2
Now, by <u>REMAINDER THEOREM</u>:
Dividend = (Divisor x Quotient) + Remainder
If ( x -3 ) divides the given polynomial with a remainder -2.
⇒ x = 3 is a solution of given polynomial E(x) - (-2) =
= S(x)
Now, S(3) = 0
⇒
or, p =1 5
Hence, for p = 15, leaves a remainder of -2 when divided by (x-3).
Answer:
360
Step-by-step explanation:
All circles can be divided into 360 units called degrees. Since there is 270 already we subtract 270 from 360.
360 - 270 = 90
90 + 150 + 120 = 360
If you calculated it you would get 20.25 so it is irrational
Answer:
x = -2, x = 3 − i√8, and x = 3 + i√8
Step-by-step explanation:
g(x) = x³ − 4x² − x + 22
This is a cubic equation, so it must have either 1 or 3 real roots.
Using rational root theorem, we can check if any of those real roots are rational. Possible rational roots are ±1, ±2, ±11, and ±22.
g(-1) = 18
g(1) = 18
g(-2) = 0
g(2) = 12
g(-11) = 1782
g(11) = 858
g(-22) = -12540
g(22) = 8712
We know -2 is a root. The other two roots are irrational. To find them, we must find the other factor of g(x). We can do this using long division, or we can factor using grouping.
g(x) = x³ − 4x² − 12x + 11x + 22
g(x) = x (x² − 4x − 12) + 11 (x + 2)
g(x) = x (x − 6) (x + 2) + 11 (x + 2)
g(x) = (x (x − 6) + 11) (x + 2)
g(x) = (x² − 6x + 11) (x + 2)
x² − 6x + 11 = 0
Quadratic formula:
x = [ 6 ± √(36 − 4(1)(11)) ] / 2
x = (6 ± 2i√8) / 2
x = 3 ± i√8
The three roots are x = -2, x = 3 − i√8, and x = 3 + i√8.
2^5/2^2 = 2^(5-2)
= 2^3
= 8
