I cannot do turning points.
Also, if this is from a test, it can be removed.
But here is a graph of the function.
Answer:

Step-by-step explanation:
as if we form an imaginary triangle with this line as hypotenuse
we get
- base = 3 units
- perpendicular = 4 units
using Pythagoras theorem:-
hyponteuse ² = perpendicular ² + base²
hyp² = 4² + 3²
hyp² = 16 + 9

hyp = 5 units

The answer:
first of all, we should know that the expression of a vector V (a, b) can be written as follow:
V = r (Vx i + Vyj), where r is the length of the vector, it is r = sqrt(V²x + V²y)
Vx is the component lying on the x-axis and Vy on the y-axis
<span>v ⃗ lies in Quadrant II, means Vx is less than 0 (negative)
</span>
so Vx= -r sin30° and Vy= rcos30°
r= <span>‖v ⃗ ‖=4√3
</span>
so we have v = - 4√3sin30° i + 4√3 cos30° j
the components are
v(- 4√3sin30°, 4√3 cos30°) = (-2√3, 4√3 cos30°)
Answer:
4(x + 1) and 4(x - (-1))
Step-by-step explanation:
4(-1 + 1) = 4(0) = 0
(4 (-1) + 5) = -4 +5 = -1
4(-1 - 1) = 4(-2) = -8
(5 - 4(-1)) = 5 + 4 = 9
4(-1 - (-1)) = 4(0) = 0
4 (-1 + (-1)) = 4(-2) = 8
For a fraction, if the denominator turns to 0, the fraction becomes undefined, and therefore, that's a restriction on a rational.
now, what values of "x" makes the denominator 0? let's check,
x+2 = 0
x = -2
so, if "x" ever becomes -2, then you'd get

so, the domain, or values "x" can take on safely, are any real numbers EXCEPT -2.