I haven't learned antiderivitives yet but I can try to logic it
<span>First find f′ and then find f. f′′(x)=3x^3+6x^2−x+2, f′(1)=9, f(1)=−7.
we reverse chain rule
3x^3, we know that it was a 4th degree thing, and the coefient is 3, so
4*what=3?, answer is 3/4
3/4x^4
6x^2
we know it was x^3, and the coefient is now 6 so
3*what=6? what=2
2x^3
-1x, the power was 2 and coefient is now -1, so
2 times what=-1?, -1/2
-1/2x^2
2, that is from 2x
so
</span>
<span>3/4x^4+2x^3-1/2x^2+2x=f'(x)
test x=1
(3/4)(1)+2(1)-(1/2)(1)+2(1)=
3/4+2-2/4+2=
4 and 1/4 we need to get it to 9
4 and 1/4 +what=9
answer is 4 and 3/4
so we add that to the end since it will become 0 from derivitive
</span>
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+4 and 3/4
now reverse drivitive again
3/4x^4
exponent is 5 and coefient is 3/4
5 times what=3/4? answer is 3/20
3/20x^5
2x^3
exponent should be 4 and coefient is 2
4 times what=2? answer is 1/2
1/2x^4
-1/2x^2
exponent should be 3 and coefient is -1/2
3 times what=-1/2? answer is -1/6
-1/6x^3
2x
exponent should be 2 and coefient is 2
2 times what=2? answer is 1
1x^2
4 and 3/4 turns to (4 and 3/4)x
</span>
<span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x
try evaluating it for x=1
f(1)=(3/20)+(10/20)-(10/50)+1+(19/4)
f(1)=6 and 7/30
what do we add to get -7
-13 and 7/30
</span>
<span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+(4 and 3/4)x-13 and 7/30
</span>
</span>ANSWER
<span>f'(x)=3/4x^4+2x^3-1/2x^2+2x+19/4
</span><span>f(x)=3/20x^5+1/2x^4-1/6x^3+x^2+19/4x-187/30</span>
Answer:
Now, we’re going to consider an example of proportional relationship in our everyday life: When we put gas in our car, there is a relationship between the number of gallons of fuel that we put in the tank and the amount of money we will have to pay. In other words, the more gas we put in, the more money we’ll pay.
Step-by-step explanation:
hope this helps
Answer:
(10, 15)
Step-by-step explanation:
To get the origin of the equation 2y+3x = 10, we need to get the x and y-intercept of the line.
x-intercept occurs at y = 0
If y = 0
2(0)+3x =10
3x =10
x = 10/3
x = 1.33
y-intercept occurs at x = 0
If x = 0
2y+3(0) =10
2y =10
y = 10/2
y = 5
Hence the coordinate at the origin is (10/3, 5). If this coordinate is dilated by 3, the required coordinate will be at (10/3*3, 5*3) = (10, 15)
Hence the required coordinate is (10, 15)
Pretty sure it is
shift 1 left
i might be wrong
