3 years ago

My teacher never taught us this so idk how to do it

Mathematics

1 answer:

Verdich [7]3 years ago

6 0

${x}^{3} = 6\Leftrightarrow \sqrt[3]{ {x}^{3} } = \sqrt[3]{6} \Leftrightarrow x = \sqrt[3]{6}$

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5y^2-6y-11-6y^2+2y+5

shusha [124]

Answer:

-y² - 4y - 6

Step-by-step explanation:

Step 1: Write expression

5y² - 6y - 11 - 6y² + 2y + 5

Step 2: Combine like terms (y²)

-y² - 6y - 11 + 2y + 5

Step 3: Combine like terms (y)

-y² - 4y - 11 + 5

Step 4: Combine like terms (constants)

-y² - 4y - 6

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3 years ago

Determine The missing number in the equation <br><br> 3 + 9= +4

Bad White [126]

3 + 9 = 12/3 = positive 4 the missing number in the equation is 12/3.

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Artemon [7]

Answer:

$\frac{3}{2}$

Step-by-step explanation:

$\frac{1}{2}$ ÷ $\frac{1}{3}$

The reciprocal of $\frac{1}{3}$ is 3, so finding the reciprocal will replace the division sign with a multiplication sign.

= $\frac{1}{2}$ x 3

= $\frac{3}{2}$ or 1 $\frac{1}{2}$ or 1.5

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Rashid [163]

$x = \frac{ -2 \pm \: \sqrt{ {2}^{2} - 4 \times 1 \times 10 } }{2} \\ \\ x = \frac{ - 2 \pm 6i}{2} \\ \\ \boxed{ \red{ \huge{x = - 1 \pm \: 3i}}}$

$\boxed{ \red{ \huge{answer = d}}}$

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devlian [24]

Can you send a picture?

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