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dimaraw [331]
3 years ago
7

Nathaniel purchases a one year membership pass to an art museum as a member he receives a discounted entrance fee the total cost

for the year f(x) after c visits to the art museum is shown on the graph below

Mathematics
2 answers:
shutvik [7]3 years ago
4 0

make me brainliest please

Arturiano [62]3 years ago
3 0
For this case, we must find the equation of the line.
 The generic equation of the line is:
 y-yo = m (x-xo)

 The slope of the line is:
 m =  \frac{y2-y1}{x2-x1}
 Substituting values we have:
 m = \frac{15-12}{2-0}
 Rewriting:
 m = \frac{3}{2}
 m = 1.5
 We now choose an ordered pair:
 (xo, yo) = (0, 12)
 Substituting values we have:
 y-12 = 1.5 (x-0)
 Rewriting the equation:
 y= 1.5x+12
 For 20 visits, we evaluate the equation when x = 20.
 We have then:
 y= 1.5(20)+12
 y= 30+12
 y= 42
 Answer:
 
The discounted entrance fee is 1.5$. The total cost is 42$ after 20 visits
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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
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Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

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y = e^(-5t)sin5t

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at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

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is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

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= t

z = z(0) + tz'(0)

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A great form to prove this is by using a calculator and dividing -9 by 6 this should get you the answer of 1.5!

Hope this helps!
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