1. V = lwh
V = (8)(4)(5)
V = (32)(5)
V = 160 units³
2. V = lwh + lwh
V = (4)(2)(1) + (3)(1)(1)
V = (8)(1) + (3)(1)
V = 8 + 3
V = 11 units³
3. V = leh + s³
V = (9)(3)(4) + (3)³
V = (27)(4) + 27
V = 108 + 27
V = 135 units³
4. V = lwh
V = (3)(7)(2)
V = (21)(2)
V = 42 units³
Let the value of the car be represented by V and the amount of years by y.
This gives us the following formula:
V = 25,635 - 3000y
(This is because we start with a value of $25,635 and the value decreases by $3,000 every year 'y')
Now, we want to know when the car is worth $3,135, so we know V = 3,135
Now we can make up our equation:
25,365 - 3,000y = 3,135
Collecting terms gives us:
-3,000y = -22,500
Finally we divide by -3,000 to find 'y'
y = -22,500 / -3,000 = 7.5
Hence, the car will be worth $3,135 after 7.5 years.
Answer:
1.2 * 10^3
Step-by-step explanation:
3.12 * 10^8
=========
2.6 * 10^5
Start by doing 3.12 / 1.6 = 1.2 and that is the correct number of sig digs.
Now get the power on the 10. When dividing, the powers subtract.
10^(8 - 5)
10^ 3
The answer is 1.2 * 10^3
Answer:
1.5x = 6
Step-by-step explanation:
This represents 1.5 times the amounts a bucket holds. (I'm assuming you mean x when you typed z)
The probability is 0.2743.
Calculating the z-score for this time, we have:
z = (X-μ)/σ
z = (96-90)/10 = 6/10 = 0.6
Using a z-table (http://www.z-table.com) we see that the area to the left of this, less than this score, is 0.7257. This means the area greater than this would be 1-0.7257 = 0.2743.
