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Aleks [24]
3 years ago
8

If an athlete can bike 6 miles in 25 minutes, how many miles will he bike in an hour and half if he continues to bike at the sam

e rate?
Mathematics
1 answer:
Len [333]3 years ago
8 0

Answer:

21.6 miles

Step-by-step explanation:

1 hour and a half is 90 minutes

90 divided by 25 is 3.6

3.6 x 6 = 21.6

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If 60 newspapers cost $27, find the cost of 16
Tju [1.3M]
16 newspapers cost $7.20
3 0
3 years ago
Simplify 17^2 and 18.79^2.
Westkost [7]

17^2 is 289

18.79^2 is 353.0641

7 0
3 years ago
which ordered pair could be added to the relation below to ensure it continues to be a function? (-7,9) (4,-1) (0,5) (-2,-2)
marin [14]

Answer:

[see below]

Step-by-step explanation:

A function's inputs do not repeat. This means that any point with the x-value not repeated with the other points can be added to ensure that it continues as a function.

In this scenario:

{x| x ≠ -7, 4, 0, -2}

A point that does not have the x-value of -7, 0, 4, and -2 could be added to the relation to ensure it continues to be a function.

Hope this helps.

4 0
3 years ago
How are exponents and radicals used to present roots of real numbers
MissTica

Answer:

       \sqrt[n]{a}  =a^{\frac{1}{n}}

Explanation:

Roots of real numbers can be represented by <em>radicals</em> or by<em> exponents. </em>

First, I present some examples to show how exponents and radicals are related, and then generalize.

      \sqrt{4}=4^{(\frac{1}{2})}=(2^2)^\frac{1}{2}=(2)^{\frac{2}{2}}=2^1=2\\\\\\\sqrt{25}=(25)^{\frac{1}{2}}=(5^2)^{\frac{1}{2}}=(5)^{\frac{2}{2}}=5^1=5

       \sqrt[3]{8}=(8)^{\frac{1}{3}}=(2^3)^{\frac{1}{3}}=(2)^{\frac{3}{3}}=2^1=2

When you write 5² = 25, then 5 is the square root of 25.

And in general, if n is a positive integer and a^n=x , then a is the nth root of x.

Also, if n even (and positive)  and a is positive, then a^{\frac{1}{n}}   is the positive nth root of a

Thus,

       \sqrt[n]{a}  =a^{\frac{1}{n}}

5 0
3 years ago
Right triangle ABC is shown. Which of these is equal to cos(A)?
REY [17]
Answer: C

cosA=AC/AB

sinB=AC/AB

hence cosA=sinB
7 0
3 years ago
Read 2 more answers
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