Really hope you can read cursive and I really hope this helps! (:
Direct variation has this equation:
y = kx
where k is the constant of variation
y = -5 ; x = -15
y = kx
-5 = k(-15)
-5/-15 = k
1/3 = k
Choice D. y = 1/3 x
Answer:
infinite
Step-by-step explanation:
Answers:
k = 13The smallest zero or root is x = -10
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Work Shown:
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.
Answer:
32.4
Step-by-step explanation:
prior + 8.1 = 40.5 . . . . . . seems to model the problem statement
prior = 32.4 . . . . . . . subtract 8.1 from both sides
Prior to the increase the percent was 32.4.
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<em>Comment on the problem statement</em>
When you're talking about a percentage increase in a percentage, it is almost never clear whether you're talking about the percentage of the underlying number, or the percentage of the percentage.
Here, we assume the 8.1 is a percentage of working students, not a percentage of the percentage of workings students. If you actually intend the latter, the percentage before the increase was about 37.465%.
