Pat found a wooden box in his

One boat tows another boat by means of a tow line, which is under a constant tension of 465 N. The boats move at a constant spee

Ludmilka [50]

Answer:

Work done, W = 141174 Joules

Explanation:

It is given that,

Constant tension acting on the boat, T = F = 465 N

Speed of the boat, v = 4.6 m/s

Time, t = 1.1 min = 66 seconds

Let W is the work done by the tension. It is equal to the product of force and displacement. It is given by :

$W=F\times d$

Since, $d=vt$

$W=F\times v\times t$

$W=465\ N\times 4.6\ m/s\times 66\ s$

W = 141174 Joules

So, the work is done by the tension is 141174 Joules. Hence, this is the required solution.

6 0

3 years ago

Explain why not everyone can become a bodybuilder, even if they train hard enough.

Anni [7]

People have diffrent body builds and bone structure

5 0

4 years ago

The density of air under normal conditions is about 1.2 kg/m3. For a wind speed of 10 m/s, find

den301095 [7]

Answer:

The density’ is 5.46

Explanation:

3 0

3 years ago

An ideal gas in a sealed container has an initial volume of 2.50 L. At constant pressure, it is cooled to 21.00 ∘C, where its fi

goblinko [34]

<u>Answer:</u> The initial temperature of the system comes out to be 147 °C

<u>Explanation:</u>

To calculate the initial temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=2.50L\\T_1=?K\\V_2=1.75L\\T_2=25^oC=(25+273)K=294K$

Putting values in above equation, we get:

$\frac{2.50L}{T_1}=\frac{1.75L}{294K}\\\\T_1=420K$

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

$T(K)=T(^oC)+273$

$420=T(^oC)+273\\T(^oC)=147^oC$

Hence, the initial temperature of the system comes out to be 147 °C

6 0

4 years ago

A student throws a set of keys vertically upward to her sorority sister, who is in a window 3.50 m above. The second student cat

Mkey [24]

Answer:

a) 8.58 m/s upward

b) -2.211 m/s downward

Explanation:

Let gravitational acceleration g = -9.81m/s2. This is negative because it deceleration the upward motion of the key.

(a)We have the following equation of motion

$s = v_0t + gt^2/2$

where $v_0$ is the initial upward velocity of the keys, t = 1.1s is the time it takes for the keys to travel a distance of s = 3.5 m

$3.5 = v_01.1 - 9.81*1.1^2/2$

$3.5 = 1.1v_0 - 5.94$

$1.1v_0 = 3.5 + 5.94 = 9.44$

$v_0 = 9.44 / 1.1 = 8.58 m/s$

So the keys were thrown initially upward with a speed of 8.58 m/s

(b) If the initial velocity of the key is 8.58 m/s and it is subjected to a deceleration of 9.81m/s2 for 1.1s then the velocity right at the 1.1s instant is

$v = v_0 + gt = 8.58 - 9.81*1.1 = -2.211 m/s$

So they keys would have a downward speed of 2.211 m/s

5 0

3 years ago