Given mass= 1kg
Weight on earth = mg(gravity of earth) = 9.8N
weight on moon = mg(gravity of moon)= 1.62N
weight on outer space mg(gravity outer space = 0) = 0N
Answer:
6.72 m/s
Explanation:
recall that the equations of motion may be expressed as
v² = u² + 2as
where,
v = final velocity,
u = initial velocity = 0 m/s because it is stationary before it starts falling
a = acceleration (in this case because it is falling, it is the acceleration due to gravity = 9.81 m/s²)
s = distance traveled = 2.3m
in our case, if we neglect air resistance, then we simply substitute the known values above into the equation of motion.
v² = u² + 2as
v² = 0² + 2(9.81)(2.3)
v² = 45.126
v = √45.126
v = 6.72 m/s
Answer:
constant acceleration
Explanation:
I may be wrong, but I'm almost positive cuz I am also taking physics. ;)
The desk is in equilbrium, so Newton's second law gives
∑ <em>F</em> (horizontal) = <em>p</em> - <em>f</em> = 0
∑ <em>F</em> (vertical) = <em>n</em> - <em>mg</em> = 0
==> <em>n</em> = <em>mg</em>
==> <em>p</em> = <em>f</em> = <em>µn</em> = <em>µmg</em> = 0.400 (80.0 kg) <em>g</em> = 313.6 N
The student pushes the desk 3.00 m, so she performs
<em>W</em> = (313.6 N) (3.00 m) = 940.8 Nm ≈ 941 J
of work.
