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3 years ago

PLEASE HELP LAW OF COSINES

Mathematics

2 answers:

RoseWind [281]3 years ago

8 0

Answer:

34 degrees

Step-by-step explanation:

edg quiz

chubhunter [2.5K]3 years ago

7 0

The Law of Cosine states
cos $C=(a^2+b^2-c^2)/2ab$

so plugging in the numbers gives us

cos $J=(13^2+19^2-11^2)/2(13*19) = 409/494$

We now have cosJ so plug that into your calculator and find arccos (arccos(cos(J)) = J)
arccos $(409/494)=34.11$
rounding your answer will give you 34°

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20 POINTS / WILL GIVE BRAINLIEST

padilas [110]

Answer: Total Volume = 15π + 18 π= 33π cubic mm

Step-by-step explanation:

What is the volume of the composite figure? Leave the answer in terms of π.

_33π mm3

We have a cone here conjoined to a semi-sphere.

Cone volume: C = (1/3)*(πr^2) * h

semi-sphere volume : V = (1/2)* (4/3) * (π * r^3)

r = 3 mm and h = 5mm

so C = (1/3)*(π (3)^2) * 5 = 15π cubic mm

V = (1/2)* (4/3) * (π * 3^3) = 18 π cubic mm

Total Volume = 15π + 18 π= 33π cubic mm

3 0

3 years ago

7 to the negative 3rd porwer times 7 to the negative 2nd porwer times 2 the 0 power divided by 7 to negative 1st power times 7 t

Jobisdone [24]

oof

remember some rules

(a/b)(c/d)=(ac)/(bd)

$\frac{x^a}{x^b}=x^{a-b}$

$x^0=1$

$(x^a)(x^b)=x^{a+b}$

$x^{-a}=\frac{1}{x^a}$

$\frac{(7^{-3})(7^{-2})(2^0)}{(7^{-1})(7^{-4})(2^3)}=$

$\frac{(7^{-3-2})(2^0)}{(7^{-1-4})(2^3)}=$

$\frac{(7^{-5})(2^0)}{(7^{-5})(2^3)}=$

$(\frac{7^{-5}}{7^{-5}})(\frac{2^0}{2^3})=$

$(7^{-5-(-5)})(2^{0-3})=$

$(7^0)(2^{-3})=$

$\frac{1}{2^3}=$

$\frac{1}{8}$

7 0

3 years ago

Write down down an equation of a line that is parallel to the line with the equation y=7-x

Bingel [31]

Answer:

y=8-x or y=9-x or y=243-x (The spot where the 8 is can be any number as long as the number infront of the 0 is still -1)

Step-by-step explanation:

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3 years ago

Will name the brainliest

Margaret [11]

Answer:

sin A = 13/85

Step-by-step explanation:

Opposite Angle A is side BC, of length 13. The length of the hypotenuse is 85. The sine function is defined as the ratio opp/hyp. In this problem that ratio is

opp

------ = sin A = 13/85

hyp

We use the inverse sine function arcsin x to determine Angle A:

A = arcsin 13/85 = 8.8 degrees

3 0

3 years ago

Read 2 more answers

Determine the length of the leg of a 45o – 45o – 90o triangle with a hypotenuse length of 15 inches. ( ANSWER NEEDS TO BE IN RED

SIZIF [17.4K]

Answer:

The lenghts of both legs: $\frac{15\sqrt{2}}{2}\ inches$

Step-by-step explanation:

By definition, when a triangle has angles that measures 45°, 45° and 90°, its legs are congruent.

Then, knowing the lenght of the hypotenuse, we can find the lenght (in inches) of any leg of the given triangle by applying the Trigonometric Identity $sin\alpha=\frac{opposite}{hypotenuse}$ :

$sin(45\°)=\frac{leg}{15}\\\\leg=\frac{15}{\sqrt{2}}$

Finally, simplifying, we get:

$leg=\frac{15(\sqrt{2})}{(\sqrt{2})(\sqrt{2})}=\frac{15\sqrt{2}}{2}$

3 0

3 years ago