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Genrish500 [490]
3 years ago
14

What is the solution to 5/6x-1/3 is greater than 1 1/3

Mathematics
2 answers:
kap26 [50]3 years ago
8 0

Answer:x>2

Step-by-step explanation:

VARVARA [1.3K]3 years ago
7 0

Answer:

The solution of the expression is x>2    

Step-by-step explanation:

Given : Expression \dfrac{5}{6}x-\dfrac{1}{3} is greater than 1 \dfrac{1}{3}

To find : The solution of teh expression ?

Solution :

According to question,

\dfrac{5}{6}x-\dfrac{1}{3}>1 \dfrac{1}{3}

\dfrac{5}{6}x-\dfrac{1}{3}>\dfrac{4}{3}    

Adding \frac{1}{3} both side,

\dfrac{5}{6}x-\dfrac{1}{3}+\dfrac{1}{3}>\dfrac{4}{3}+\dfrac{1}{3}            

\dfrac{5}{6}x>\dfrac{5}{3}          

Multiply \frac{6}{5} both side,

\dfrac{5}{6}x\times \frac{6}{5}>\dfrac{5}{3}\times\frac{6}{5}      

x>2                    

Therefore, The solution of the expression is x>2        

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y=mx+b

m=slope
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y=mx+b
y=(4/5)x-1

Answer: the equation of the line with slope=4/5, and y-intercept=-1 would be:
y=(4/5)x-1
5 0
3 years ago
Match each measurement with the correct unit.
makvit [3.9K]

Answer:

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3. area = m²

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Step-by-step explanation:

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6 0
3 years ago
Rewrite the expression in the form x^n<br><br> Thank You
Lisa [10]

Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
The question is in the picture.
dangina [55]
<h2><u>Part A:</u></h2>

Let's denote no of seats in first row with r1 , second row with r2.....and so on.

r1=5

Since next row will have 10 additional row each time when we move to next row,

So,

r2=5+10=15

r3=15+10=25

<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>

r1=5=5+0=5+0×10=5+(1-1)×10

r2=15=5+10=5+(2-1)×10

r3=25=5+20=5+(3-1)×10

<u>So for nth row,</u>

rn=5+(n-1)×10

Since 5=r1 and 10=common difference (d)

rn=r1+(n-1)d

Since 'a' is a convention term for 1st term,

<h3><u>⇒</u><u>rn=a+(n-1)d</u></h3>

which is an explicit formula to find no of seats in any given row.

<h2><u>Part B:</u></h2>

Using above explicit formula, we can calculate no of seats in 7th row,

r7=5+(7-1)×10

r7=5+(7-1)×10 =5+6×10

r7=5+(7-1)×10 =5+6×10 =65

which is the no of seats in 7th row.

8 0
3 years ago
when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%​
Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%​

  • Selling price = cost price - discount ⇒ discount case
  • Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = \frac{160}{90}=\frac{16}{9}

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = \frac{20}{100} × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by \frac{16}{9} to find x

∵ 0.8x = \frac{16}{9}

- Divide both sides by 0.8

∴ x = \frac{20}{9}

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is \frac{20}{9}

- Find 20% of \frac{20}{9}

∵ Profit = 20% × \frac{20}{9} = \frac{20}{100}.\frac{20}{9}=\frac{4}{9}

- Add \frac{4}{9} to cost price to find the selling price

∴ The selling price of an orange = \frac{20}{9} + \frac{4}{9}

∴ The selling price of an orange = \frac{24}{9}

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ \frac{24}{9}

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0
3 years ago
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