Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
Answer:
The answere is C
Step-by-step explanation:
Subtract what is to the right of the equal sign form both side of the equation but any way the answer is 0
Answer:
31
Step-by-step explanation:
4 squared is 16, and 5 times 3 is fifteen if you add them you get 31
By the polynomial remainder theorem, the remainder upon dividing
by
will be the value of
.
... | 1 ... -6 ... -4 ... -6 .... -2
3. | .. ... 3 ... -9 ... -39 .. -135
--------------------------------------
... | 1 ... -3 ... -13 . -45 .. -137
So you have
which means
.