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3 years ago

Find five rational numbers between 5/4 and 2

Mathematics

2 answers:

Flauer [41]3 years ago

8 0

Answer:

29/20, 33/20, 7/4, 37/20, 39/20.

Hope this helps.

KATRIN_1 [288]3 years ago

6 0

Answer:

26/20 ; 27/20 ; 28/20 ; 29/20 ; 30/20

Step-by-step explanation:

First we try to give both number the same denominator like this :

5/4 = (5*5)/(4*5) = 25/20

2 = 2/1 = (2*20)/(1*20) = 40/20

we get :

5/4 = 25/20 < 26/20 < 27/20 < 28/20 <29/20 < 30/20 < 40/20 = 2

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Suppose that a market research firm is hired to estimate the percent of adults living in a large city who have cell phones. 500

Alborosie

Answer:

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 500, \pi = \frac{421}{500} = 0.842$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 - 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.81$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.842 + 1.96\sqrt{\frac{0.842*0.158}{500}} = 0.874$

The 95% confidence interval estimate for the true proportion of adults residents of this city who have cell phones is (0.81, 0.874).

6 0

3 years ago

Need help solving this please

Aloiza [94]

Answer:

A) x=39

Step-by-step explanation:

117 = 3x

117 divided by 3 = 39

3x = 117

3(39) = 117

117 = 117

A) x = 39

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