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blagie [28]
2 years ago
12

Using the order of operations, which operation in the expression 3x2-2³÷4 should be completed first

Mathematics
1 answer:
faust18 [17]2 years ago
6 0

Answer:

C.  Cube 2.

Step-by-step explanation:

Using PEMDAS  the first operation to be done is E (Exponent)  which is

2³.

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What is Simplest form
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Choose the model that represents the function
kirill [66]

Answer:

OPTION D

Step-by-step explanation:

We have to determine which option determines the function given above.

To determine the function, just substitute the values and compare LHS and RHS.

we have $ f(4) = 18 $

$ f(-2) = -12 $

$ f(0) = -2 $

$ f(-3) = -17 $

Here, $ x $ is the domain and $ f(x) $ is the co-doamin.

Therefore, $ x = \{4, -2, 0, -3\} $

Now, OPTION A: $ f(x) =  2x - 5 $

Substitute x = 4. We get f(x) = 3 $ \ne $ 18.

So, OPTION A is rejected.

Similarly, OPTION B: $ f(x) = 5x + 2 $

Substitute x = 4. We get f(4) = 22 $ \ne $18.

It is rejected as well.

Now, for OPTION C: $ f(x) = \frac{x}{2} - 5 $

Substitute x = 4. We get f(4) = -3 $ \ne $ 18.

So, OPTION C is also rejected.

OPTION D: $ f(x) =  5x - 2 $

Substitute x = 4. We get f(4) = 18.

Substitute the remaining points in domain as well. We notice that it exactly matches the given function. So, OPTION D is the answer.

8 0
3 years ago
What is the solution to the following equation? x2 + 3x + 4 = 0​
andreev551 [17]

Answer:

x=\dfrac{-3\pm \sqrt7i}{2}

Step-by-step explanation:

The given equation is x^{2}+3x+4=0.

We need to find the solution of the above equation.

The solution of an equation ax^2+bx+c=0 is :

x=\dfrac{-b\pm \sqrt{b^2-4ac} }{2a}

We have, a = 1, b = 3 and c = 4

x=\dfrac{-3+ \sqrt{(3)^2-4(1)(4)} }{2}, \dfrac{-3- \sqrt{(3)^2-4(1)(4)} }{2}\\\\=\dfrac{-3+\sqrt{9-16}}{2}, \dfrac{-3-\sqrt{9-16}}{2}\\\\=\dfrac{-3\pm \sqrt7i}{2}

So, the solution of the given equation is \dfrac{-3\pm \sqrt7i}{2}.

5 0
3 years ago
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