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Mathematics

2 answers:

ankoles [38]2 years ago

7 0

Answer:

1 = A

2 = A

3 = D

4 = D

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frez [133]2 years ago

4 0

7. $\frac{1}{127}$

8. $a^{5}b^{6}c^{4}$

9. $a^{2} b^{2} c^{3}$

10. $\frac{1}{x^{3} }$

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Wht are the next three terms in the sequence -3 6 15 24

kogti [31]

6--3=9
15-6=9,
so
24+9=33,
33+9=42,
42+9=51
33,42,51

4 0

2 years ago

Read 2 more answers

In a shipment of 56 vials, only 13 do not have hairline cracks. If you randomly select 3 vials from the shipment, in how many wa

Elden [556K]

Answer: 27434

Step-by-step explanation:

Given : Total number of vials = 56

Number of vials that do not have hairline cracks = 13

Then, Number of vials that have hairline cracks =56-13=43

Since , order of selection is not mattering here , so we combinations to find the number of ways.

The number of combinations of m thing r things at a time is given by :-

$^nC_r=\dfrac{n!}{r!(n-r)!}$

Now, the number of ways to select at least one out of 3 vials have a hairline crack will be :-

$^{13}C_2\cdot ^{43}C_{1}+^{13}C_{1}\cdot ^{43}C_{2}+^{13}C_0\cdot ^{43}C_{3}\\\\=\dfrac{13!}{2!(13-2)!}\cdot\dfrac{43!}{1!(42)!}+\dfrac{13!}{1!(12)!}\cdot\dfrac{43!}{2!(41)!}+\dfrac{13!}{0!(13)!}\cdot\dfrac{43!}{3!(40)!}\\\\=\dfrac{13\times12\times11!}{2\times11!}\cdot (43)+(13)\cdot\dfrac{43\times42\times41!}{2\times41!}+(1)\dfrac{43\times42\times41\times40!}{6\times40!}\\\\=3354+11739+12341=27434$