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Masja [62]
3 years ago
11

Solve using the standard algorithm the area model the distributive property or the partial products method 2,809x4

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0

Answer:

11,236

Step-by-step explanation:

i think this might be the answer but if it not alseat I try helping

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I need help with this if anyone can help
Fiesta28 [93]

Answer: \Large\boxed{Fourth~Choice.~f(x)=2-i}

Concept:

Here, we need to know the power of imaginary numbers

i = √(-1)

i² = -1

i³ = -i

i⁴ = 1

Solve:

<u>Given function expression</u>

f(x)=x^3-2x^2

<u>Given the requirement of the question</u>

To find the expression for f(i)

<u>Substitute values into the expression</u>

f(x)=(i)^3-2(i)^2

<u>Simplify the exponents</u>

f(x)=(-i)-2(-1)

<u>Expand the parenthesis</u>

f(x)=-i-(-2)

\Large\boxed{f(x)=2-i}

Hope this helps!! :)

Please let me know if you have any questions

3 0
1 year ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B1024%7D%20" id="TexFormula1" title=" \sqrt{1024} " alt=" \sqrt{1024} " align="abs
4vir4ik [10]
96
____________________
8 0
3 years ago
What is the average of 4 1/2, 3 1/3, 2, 2 1/6? I will give brainleist.
kotykmax [81]

Answer:

3

Step-by-step explanation:

  4 1/2 + 3 1/3 + 2 + 2 1/6

= 4 3/6 + 3 2/6 + 2 + 2 1/6

= 4 + 3 + 2 + 2 + 3/6 + 2/6 + 1/6

= 11 + 6/6

= 11 + 1

= 12

There are 4 numbers, therefore average = 12 ÷ 4 = 3

7 0
2 years ago
A certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder. In
lord [1]

Answer:

95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

Step-by-step explanation:

We are given that a certain geneticist is interested in the proportion of males and females in the population who have a minor blood disorder.

A random sample of 1000 males, 250 are found to be afflicted, whereas 275 of 1000 females tested appear to have the disorder.

Firstly, the pivotal quantity for 95% confidence interval for the difference between population proportion is given by;

                        P.Q. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of males having blood disorder= \frac{250}{1000} = 0.25

\hat p_2 = sample proportion of females having blood disorder = \frac{275}{1000} = 0.275

n_1 = sample of males = 1000

n_2 = sample of females = 1000

p_1 = population proportion of males having blood disorder

p_2 = population proportion of females having blood disorder

<em>Here for constructing 95% confidence interval we have used Two-sample z proportion statistics.</em>

<u>So, 95% confidence interval for the difference between the population proportions, </u><u>(</u>p_1-p_2<u>)</u><u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < {(\hat p_1-\hat p_2)-(p_1-p_2)} < 1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

P( (\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } < (p_1-p_2) < (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} } ) = 0.95

<u>95% confidence interval for</u> (p_1-p_2) =

[(\hat p_1-\hat p_2)-1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }, (\hat p_1-\hat p_2)+1.96 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }]

= [ (0.25-0.275)-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} }, (0.25-0.275)+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{1000}+ \frac{0.275(1-0.275)}{1000}} } ]

 = [-0.064 , 0.014]

Therefore, 95% confidence interval for the difference between the proportions of males and females who have the blood disorder is [-0.064 , 0.014].

8 0
3 years ago
Jacob is 3 years younger than his friend Noah. Noah is x years old.
irinina [24]

Answer:

x + 4  

Step-by-step explanation:

Noah's age = x

Jacob's age = x – 3

In seven years,

Jacob's age = x – 3 + 7

Jacob's age = x + 4

5 0
2 years ago
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