9514 1404 393
Answer:
9.6 kW
Step-by-step explanation:
The product of volts and amps is watts. Here, that product is ...
(240 V)(40 A) = 9600 W
1000 W is 1 kW, so this quantity is 9.6 kW
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This tells the power consumption. The "rating" may be different.
12% of 130 is 15.6 hope it helps!
Answer:
In 1981, the Australian humpback whale population was 350
Po = Initial population = 350
rate of increase = 14% annually
P(t) = Po*(1.14)^t
P(t) = 350*(1.14)^t
Where
t = number of years that have passed since 1981
Year 2000
2000 - 1981 = 19 years
P(19) = 350*(1.14)^19
P(19) = 350*12.055
P(19) = 4219.49
P(19) ≈ 4219
Year 2018
2018 - 1981 = 37 years
P(37) = 350*(1.14)^37
P(37) = 350*127.4909
P(37) = 44621.84
P(37) ≈ 44622
There would be about 44622 humpback whales in the year 2018
notice, the denominator for each fraction is the same, thus the LCD is just 3.
700-175=525
525:35=15
He must save $35 during 15 weeks to have his new computer
