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Mazyrski [523]
2 years ago
8

Jadah bikes 45 miles in 3 hours. At this rate, how far does she go in 8 hours?

Mathematics
1 answer:
Ber [7]2 years ago
8 0

Answer:

120 miles

Step-by-step explanation:

45 divided by 3 equals to 15 and 15 times 8 equals 120.

45 / 3 = 15

15 x 8 = 120

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What is a disadvantage of overpaying your taxes during the year?
Otrada [13]
The disadvantage of overpaying your taxes during the year is that you cannot use the money or draw interest on it until after you get your tax refund.

If you are overpaying your taxes, the government is holding that extra money for you. At the end of the tax year when you file your taxes, they will give you the extra money back that you overpaid.

However, you don't receive any interest on the extra money that was held.
5 0
2 years ago
Solve the following equation by completing the square. 3x^2-3x-5=13
mr Goodwill [35]

we'll start off by grouping some

\bf 3x^2-3x-5=13\implies (3x^2-3x)-5=13\implies 3(x^2-x)-5=13 \\\\\\ 3(x^2-x)=18\implies (x^2-x)=\cfrac{18}{3}\implies (x^2-x)=6\implies (x^2-x+~?^2)=6

so we have a missing guy at the end in order to get the a perfect square trinomial from that group, hmmm, what is it anyway?

well, let's recall that a perfect square trinomial is

\bf \qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2

so we know that the middle term in the trinomial, is really 2 times the other two without the exponent, well, in our case, the middle term is just "x", well is really -x, but we'll add the minus later, we only use the positive coefficient and variable, so we'll use "x" to find the last term.

\bf \stackrel{\textit{middle term}}{2(x)(?)}=\stackrel{\textit{middle term}}{x}\implies ?=\cfrac{x}{2x}\implies ?=\cfrac{1}{2}

so, there's our fellow, however, let's recall that all we're doing is borrowing from our very good friend Mr Zero, 0, so if we add (1/2)², we also have to subtract (1/2)²

\bf \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2-\left[ \cfrac{1}{2} \right]^2 \right)=6\implies \left( x^2 -x +\left[ \cfrac{1}{2} \right]^2 \right)-\left[ \cfrac{1}{2} \right]^2=6 \\\\\\ \left(x-\cfrac{1}{2} \right)^2=6+\cfrac{1}{4}\implies \left(x-\cfrac{1}{2} \right)^2=\cfrac{25}{4}\implies x-\cfrac{1}{2}=\sqrt{\cfrac{25}{4}} \\\\\\ x-\cfrac{1}{2}=\cfrac{\sqrt{25}}{\sqrt{4}}\implies x-\cfrac{1}{2}=\cfrac{5}{2}\implies x=\cfrac{5}{2}+\cfrac{1}{2}\implies x=\cfrac{6}{2}\implies \boxed{x=3}

6 0
3 years ago
What is the scale factor of the dilation
Marizza181 [45]
Looking at how the image shrinked from the original, you can assume that the scale would be a fraction. Since they remained negative, then the fraction wouldn't contain a negative. Therefore the answer would be C.
8 0
2 years ago
Urgent:
rjkz [21]

Step-by-step explanation:

<h3>Given:</h3>
  • CM ⊥ AB
  • ∠3 = ∠4
<h3>To prove: </h3>
  • △AMC ≅ △BMC
<h3>Solution:</h3>
  • ∠ACM≅∠BCM - given

<u>CM⊥AB - given, therefore</u>

  • ∠AMC = 90° and ∠BMC = 90°

<u>Then</u>

  • ∠AMC ≅ ∠BMC
  • Side CM is common, therefore is congruent to itself

<u>So we have congruent two angles and a side between them on triangles AMC and BMC:</u>

  • △AMC ≅ △BMC as per ASA congruency theorem
5 0
2 years ago
In the figure given below, calculate x and y.
LekaFEV [45]

Answer:

x = 73°

        y = 39°

Step-by-step explanation:

x + 107 = 180        {Linear pair}

        x = 180 - 107         {Subtract 107 from both sides}

        x = 73°

y + 51 + 90 = 180      {straight line angles}

   y  +  141   = 180

           y = 180 - 141

          y = 39°

5 0
2 years ago
Read 2 more answers
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