Question

Sketch the asymptote and graph the function y=8/(x+3)-2

Answer 1

I dont know if we have the same assesmemt or not tue anwser would be option D

Answer 2

Answer:

Please find the attached file.

Step-by-step explanation:

Given: $y=\dfrac{8}{x+3}-2$

We need to draw the graph of function with asymptote.

For horizontal asymptote:-

$x\rightarrow \infty$

$y=\lim_{x\rightarrow \infty}(\dfrac{8}{x+3}-2)=-2$

HA: y=-2

For vertical asymptote:-

$y\rightarrow \infty$

$x+3=0$

VA: x=-3

For x-intercept, Put y=0

(1,0)

For y-intercept, Put x=0

(0,2/3)

Now we will plot on graph and draw the graph.

Please see the attachment for graph.