Given:
Number of black marbles = 6
Number of white marbles = 6
Let's determine the least number of marbles that can be chosen to be certain that you have chosen two marble of the same color.
To find the least number of marble to be chosen to be cartain you have chosen two marbles of the same color, we have:
Total number of marbles = 6 + 6 = 12
Number of marbles to ensure at least one black marble is chosen = 6 + 1 = 7
Number of marbles to ensure at least one white marble is chosen = 1 + 6 = 7
Therefore, the least number of marbles that you must choose, without looking , to be certain that you have chosen two marbles of the same color is 7.
ANSWER:
7
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Answer:
x = 
Step-by-step explanation:
To solve for x, we need to isolate it [get it alone on one side]
We should start by simplifying (combining the like-terms of our equation):
5 + 5 = 5x + 5 - 2
10 = 5x + 3
- 3 - 3 (subtract 3 from both sides to isolate x)
7 = 5x
÷5 ÷5 (divide both sides by 5 to find "1"x)
So, x =
(x = 7/5)
hope this helps!!
Answer:
33/4
Step-by-step explanation:
Let the first number be x, and the second number be y.
x - y = 4
x + y = -7
Solve for x in the first equation.
x - y = 4
x = 4 + y
Put x as (4 + y) in the second equation and solve for y.
4 + y + y = -7
4 + 2y = -7
2y = -7 - 4
2y = -11
y = -11/2
Put y as -11/2 in the first equation and solve for x.
x - y = 4
x - (-11/2) = 4
x + 11/2 = 4
x = 4 - 11/2
x = -3/2
Their product is:
-11/2 × -3/2
33/4
Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
