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2 years ago

110 cm 50 cm 140cm 90 cm -110 cm - 70 cm

Mathematics

1 answer:

mihalych1998 [28]2 years ago

3 0

Answer:

probably is 140 or is it just the whole question?

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Force of 100N Work of 1000J what was the distance

Simora [160]

Answer:

10m

Step-by-step explanation:

You use Work done=Force × Distance

So therefore 1000=100×D

Therefore D=10m

3 0

2 years ago

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What is rotational symmetry

Alisiya [41]

<span>A shape has Rotational Symmetry when it still looks the same after a rotation.</span>

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2 years ago

3x to the power of 3 + 21x squared + 36x = 0 by factoring the quadratic equation.

Diano4ka-milaya [45]

Answer:

x = 0, -4 and -3.

Step-by-step explanation:

The given expression is "3x to the power of 3 + 21x squared + 36x = 0".

We can write this expression as follows :

$3x^3+21x^2+36x=0$

Taking 3x common.

$3x(x^2+7x+12)=0\\\\3x=0\ \text{and}\ (x^2+7x+12)=0$

x = 3

$x^2+7x+12=0\\\\x^2+3x+4x+12=0\\\\x(x+3)+4(x+3)=0\\\\(x+4)(x+3)=0\\\\x=-4,-3$

Hence, the solution of the given quadratic equation are x = 0, -4 and -3.

5 0

3 years ago

What two numbers add up to 18 and multiply to 80

mestny [16]

Answer:

8 and 10

Step-by-step explanation:

First, let's look at the factors of 80.

1 • 80 = 80

2 • 40 = 80

4 • 20 = 80

5 • 16 = 80

8 • 10 = 80

Look at each pair and evaluate their sum.

1 • 80 = 80

1 + 80 = 81

2 • 40 = 80

2 + 40 = 42

4 • 20 = 80

4 + 20 = 24

5 • 16 = 80

5 + 16 = 21

8 • 10 = 80

8 + 10 = 18

Our last pairing multiplies to 80 and adds up to 18. Therefore, your answer is 8 & 10.

Hope this helps!

4 0

2 years ago

In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,

aivan3 [116]

Answer:

Case 1:

$AB = 30$

$BC = 50$

Case 2:

$AB = 15.9$

$BC = 36.7$

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

$AB^2 = AN^2 + BN^2$

This gives:

$AB^2 = 24^2 + 18^2$

$AB^2 = 576 + 324$

$AB^2 = 900$

Take square roots of both sides

$AB = \sqrt{900$

$AB = 30$

To calculate BC, we consider ANC, where:

$AC^2 = AN^2 + NC^2$

$40^2 = 24^2 + NC^2$

$1600 = 576 + NC^2$

Collect like terms

$NC^2 = 1600 - 576$

$NC^2 = 1024$

Take square roots

$NC = \sqrt{1024$

$NC = 32$

So:

$BC = NC + BN$

$BC = 32 + 18$

$BC = 50$

Case 2:

Using Pythagoras theorem in ANB, we have:

$AN^2 = AB^2 + BN^2$

This gives:

$24^2 = AB^2 + 18^2$

$576 = AB^2 + 324$

Collect like terms

$AB^2 = 576 - 324$

$AB^2 = 252$

Take square roots of both sides

$AB = \sqrt{252$

$AB = 15.9$

To calculate BC, we consider ABC, where:

$AC^2 = AB^2 + BC^2$

$40^2 = 252 + BC^2$

$1600 = 252 + BC^2$

Collect like terms

$BC^2 = 1600 - 252$

$BC^2 = 1348$

Take square roots

$BC = \sqrt{1348$

$BC = 36.7$

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

3 0

2 years ago