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igor_vitrenko [27]
3 years ago
14

Ms. Taylor's students give cards to each of

Mathematics
1 answer:
WITCHER [35]3 years ago
7 0
I think it’s 8 if I’m not mistaken
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Answer:

\frac{\sqrt{x} }{2x}

Step-by-step explanation:

Rationalize the denominator first (keep in mind we are NOT solving this because there is no equals sign here.  We are merely simplifying.)

\frac{\sqrt{5x} }{x\sqrt{20} } *\frac{\sqrt{20} }{\sqrt{20} } =\frac{\sqrt{100x} }{20x}

Now simplify by taking the square root of 100 to get:

\frac{10\sqrt{x} }{20x}

Divide numerator and denomiator by 10 to get:

\frac{\sqrt{x} }{2x}

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