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3 years ago

1. _____ any push or pull on an object

Mathematics

1 answer:

borishaifa [10]3 years ago

5 0

1. Force any push or pull on an object. 2. Displacement is an object changing position over time.

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Find the measurement of E<br> •56<br> •132<br> •51<br> •63

Burka [1]

Answer:

∠ E = 56°

Step-by-step explanation:

the external angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ MGF is an exterior angle of the triangle , then

10x + 12 = 5x - 4 + 76

10x + 12 = 5x + 72 ( subtract 5x from both sides )

5x + 12 = 72 ( subtract 12 from both sides )

5x = 60 ( divide both sides by 5 )

x = 12

Then

∠ E = 5x - 4 = 5(12) - 4 = 60 - 4 = 56°

4 0

2 years ago

Read 2 more answers

A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of

Debora [2.8K]

Answer:

$0.1546\leq \widehat{p}\leq 0.3513$

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

$\widehat{p}=\frac{x}{n}$

$\widehat{p}=\frac{19}{75}$

$\widehat{p}=0.253$

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

$=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}$

$=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}$

Confidence interval $=0.1546\leq \widehat{p}\leq 0.3513$

7 0

4 years ago

If two parallel planes are cut by a third plane, then the lines of intersection are _________.

maxonik [38]

<span>If two parallel planes are cut by a third plane, then the lines of intersection are parallel and cannot intersect one another.</span>

6 0

3 years ago

Read 2 more answers

One day at football practice, Darrell, the kicker, punted the ball so that its height in feet above the ground was given by the

nika2105 [10]

When the football is 81 feet high, it will be √ 3 / 8 seconds

<h3>Function</h3>

Function relates input to output. Therefore,

h(t) = - 16t² + 75

Therefore,

t = number of seconds

h(t) = - 16t² + 75

h(t) = 81 ft

Therefore,

81 = - 16t² + 75

- 16t² = 81 - 75

- 16t² = 6

divide both sides by -16

t² = 6 / -16

t² = - 3 / 8

square root both sides

t = √ 3 / 8 seconds

learn more on function here: brainly.com/question/4418459

6 0

2 years ago

PLEASE I need help on these 4 problems you don’t have to do them all but if you can at least do one of them TYSM

Brrunno [24]

Answer:

For right angle triangle,

we use Pythagoras theorem that is:

$c^{2} =a^{2} +b^{2}$

c = $\sqrt{a^{2} +b^{2} }$

For question 1:

c = ?

a = 40

b = 9

putting them in formula,

c = $\sqrt{40^{2} + 9^{2} }$

c = 41

For question 2:

c = ?

a = 12

b = 13

putting them in formula,

c = $\sqrt{12^{2} + 13^{2} }$

c = approximately 17.69181

For question 3:

c = 35

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$35^{2} = 20^{2} + b^{2}$

1225 = 400 + $b^{2}$

$b^{2}$ = 1225 - 400

$b^{2}$ = 825

$\sqrt{b^{2} } = \sqrt{825}$

b = 5 $\sqrt{33}$

For question 4:

c = 37

a = 20

b = ?

putting them in formula,

$c^{2} =a^{2} +b^{2}$

$37^{2} = 20^{2} + b^{2}$

1369 = 400 + $b^{2}$

$b^{2}$ = 1369 - 400

$b^{2}$ = 969

Taking square root on both sides

b = 31.12

Hope it helps.

4 0

3 years ago