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uranmaximum [27]
3 years ago
12

Solve each equation.) 9+t=35

Mathematics
2 answers:
Reptile [31]3 years ago
6 0

Answer:

t = 26

Step-by-step explanation:

Step 1: Subtract 9 from both sides.

  • 9 + t - 9 = 35 - 9
  • t = 26

Step 2: Check if solution is correct.

  • 9 + 26 = 35
  • 35=35

Therefore, t = 26.

Ugo [173]3 years ago
5 0

Answer:

The Answer of

t=35-9

t=26

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3 years ago
PROVE THAT:<br><br>cos 20° - sin 20° = ​​ \sqrt{2}sin25°<br><br>​
Lemur [1.5K]

Answer:

See below.

Step-by-step explanation:

\cos(20)-\sin(20)=\sqrt{2}\sin(25)

First, use the co-function identity:

\sin(90-x)=\cos(x)

We can turn the second term into cosine:

\sin(20)=\sin(90-70)=\cos(70)

Substitute:

\cos(20)-\cos(70)=\sqrt{2}\sin(25)

Now, use the sum to product formulas. We will use the following:

\cos(x)-\cos(y)=-2\sin(\frac{x+y}{2})\sin(\frac{x-y}{2})

Substitute:

\cos(20)-\cos(70)=-2\sin(\frac{20+70}{2})\sin(\frac{20-70}{2})\\\cos(20)-\cos(70)  =-2\sin(45)\sin(-25)\\\cos(20)-\cos(70)=-2(\frac{\sqrt{2}}{2})\sin(-25)\\ \cos(20)-\cos(70)=-\sqrt{2}\sin(-25)

Use the even-odd identity:

\sin(-x)=-\sin(x)

Therefore:

\cos(20)-\cos(70)=-\sqrt{2}\sin(-25)\\\cos(20)-\cos(70)=-\sqrt{2}\cdot-\sin(25)\\\cos(20)-\cos(70)=\sqrt{2}\sin(25)

Replace the second term with the original term:

\cos(20)-\sin(20)=\sqrt{2}\sin(25)

Proof complete.

4 0
4 years ago
(6x^3+13x^2+8x+11)/(3x+5)
makkiz [27]
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3 years ago
How many whole cubecan be cut from a cuboid measuring 33 cm by 29 CM by 18 cm
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Volume = 33 x 29 x 18
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Number of whole cubes formed by the defined volume = 17,226/3
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7 0
3 years ago
Find AM in the parallelogram if PN =15 and AO = 6. The diagram is not to scale.
valentinak56 [21]

Answer:

6

Step-by-step explanation:

The diagonals of a parallelogram bisect each other.

The diagonals are PN and MO. The point A divides PN into 2 equal segments as well as MO into 2 equal segments.

Since AO = 6, MA should also be equal. Hence, MA (or AM) = 6.

The correct answer is AM = 6

7 0
3 years ago
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