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Gre4nikov [31]
3 years ago
9

What is the area of a triangle with verticals at(-4,1),(-7,5) and (0,1)

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0

Answer:

8

Step-by-step explanation:

There are several ways of doing that, but probably the simplest one is to use the formula

\bf Area=\left| \frac{A_x(B_y-C_y)+B_x(A_y-C_y)+C_x(A_y-B_y)}{2}\right|

where the vertices are

\bf (A_x,A_y),(B_x,B_y),(C_x,C_y)

and the bars | | means that you take the positive value of the number inside. For example | -3 | = 3.

Our vertices are

\bf (A_x,A_y)=(-4,1)

\bf (B_x,B_y)=(-7,5)

\bf (C_x,C_y)=(0,1)

Replace the values in the formula and we have

\bf Area=\left| \frac{-4(5-1)-7(1-1)+0(1-5)}{2}\right|=\left| \frac{-4(4)}{2}\right|=\left| \frac{-16}{2}\right|=|-8|=8

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