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zloy xaker [14]
3 years ago
11

Mahnoor randomly selects times to walk into a local restaurant and observe the type of music being played. She found that the re

staurant was playing country 11 times, rock & roll 17 times, and blues 8 times
Mathematics
1 answer:
stiks02 [169]3 years ago
6 0

Answer:

The next time Mahnoor visits the restaurant, there is:

--31 % chance for country music

--47% chance of rock & roll

--22% chance of blues

Completed question;

Mahnoor randomly selects times to walk into a local restaurant and observe the type of music being played. She found that the restaurant was playing country 11 times, rock & roll 17 times, and blues 8 times. Use the observed frequencies to create a probability model for the type of music the restaurant is playing the next time Mahnoor walks in.

Step-by-step explanation:

Given;

The number of times they were playing each type of music;

Country = 11 times

Roll = 17 times

Blues = 8 times

Total visits of Mahnoor = 11+17+8 = 36

Developing a frequency table and probability model for the type of music the restaurant is playing the next time Mahnoor walks in.

Probability = number of favourable outcomes ÷ total number of outcomes.

Music played  |  Frequency  |  Probability

country            |  11                 |  11/36 = .31 or 31%

rock & roll        |  17                |  17/36 = .47 or 47%

blues                |  8                 |  8/36 = .22 or 22%

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My favorite pizza restaurant advertises that their average delivery time is 20 minutes. It always feels like it takes forever fo
andrezito [222]

Answer:

Population parameter(s): mean μ=20

Sample statistics: M=20.7, s=2.1

Hypotheses:

H_0: \mu=20\\\\H_a:\mu> 20

Test Statistic: t=2.357

p-value: 0.011

Reject H? YES

Conclusion (in context of the problem): There is  enough evidence to support the claim that the advertised delivery time is overly optimistic and it is larger than 20 minutes.  

<em>Is this difference practically significant? </em>No, the difference as the sample mean delivery time is under one minute of difference from the advertised time. Although it is significantly from the statistical point of view, the  difference is under 5% of the advertised delivery time.

The 99% confidence interval for the mean is (19.904, 21.496).

With this level of confidence, the null hypothesis failed to be rejected, as t=20 is a possible value for the true mean (is included in the confidence interval).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the advertised delivery time is overly optimistic and it is larger than 20 minutes.  

Then, the null and alternative hypothesis are:

H_0: \mu=20\\\\H_a:\mu> 20

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=20.7.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=2.1.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2.1}{\sqrt{50}}=0.297

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{20.7-20}{0.297}=\dfrac{0.7}{0.297}=2.357

The degrees of freedom for this sample size are:

df=n-1=50-1=49

This test is a right-tailed test, with 49 degrees of freedom and t=2.357, so the P-value for this test is calculated as (using a t-table):

P-value=P(t>2.357)=0.011

As the P-value (0.011) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the advertised delivery time is overly optimistic and it is larger than 20 minutes.  

2. We have to calculate a 99% confidence interval for the mean.

The sample mean is M=20.7.

The sample size is N=50.

The t-value for a 99% confidence interval is t=2.68.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.68 \cdot 0.297=0.796

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 20.7-0.796=19.904\\\\UL=M+t \cdot s_M = 20.7+0.796=21.496

The  99% confidence interval for the mean is (19.904, 21.496).

With this level of confidence, the null hypothesis failed to be rejected, as t=20 is a possible value for the true mean (is included in the confidence interval).

7 0
3 years ago
Help me guys? Please
AVprozaik [17]

Answer:

a :)

Step-by-step explanation:

8 0
3 years ago
Helppppp fast pleaseeeeeee
mario62 [17]

Answer:

72

Step-by-step explanation:

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7 0
3 years ago
An = a1 + (n − 1)d<br> Find the 31st term of the sequence -22, -19, -16, -13,...
JulsSmile [24]

Answer:

68.

Step-by-step explanation:

The common difference d = -19 - (-22) = 3

So the 31st term =

a31 =  -22 + (31-1)3

= -22 + 90

= 90 - 22

= 68.

4 0
3 years ago
If JKL - PNM. then M = L and the sides NP and<br> KJ are proportional.<br> True <br> Or<br> False???
nikklg [1K]

Answer:

True

Step-by-step explanation:

In similarity triangles, corresponding angles are congruent and corresponding sides are in proportion.

4 0
3 years ago
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