The sum of a rational number and an irrational number is irrational." By definition, an irrational number in decimal form goes on forever without repeating (a non-repeating, non-terminating decimal). By definition, a rational number in decimal form either terminates or repeats.

Step-by-step explanation:

However, if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational. "The product of two irrational numbers is SOMETIMES irrational." Each time they assume the sum is rational; however, upon rearranging the terms of their equation, they get a contradiction (that an irrational number is equal to a rational number). Since the assumption that the sum of a rational and irrational number is rational leads to a contradiction, the sum must be irrational.

5 0

3 years ago

A restaurant wishes to have at least one server for every 12 tables. Each of the tables in the restaurant seats four guests. If

Fiesta28 [93]

X = number of servers
y = number of guests

$\text {number of guest per table = } 4$ 

 $\text {number of tables = } \dfrac{y}{4}$

 $\text {number of servers needed = } \dfrac{y}{4} \div 12$ 

 $\text {number of servers needed = } \dfrac{y}{4} \times \dfrac{1}{12}$

$\text {number of servers needed = } \dfrac{y}{48}$

There must be at least 1 server for every 12 tables:
$x \geq \dfrac{y}{48}$

8 0

3 years ago

Solve the equation 14 = 9 - p

morpeh [17]

14 = 9 - p

Move 9 to the other side

Sign changes from +9 to -9

14-9= 9-9-p

14-9= -p

5=-p

Mutiply both sides by -1 to get + p

(5)(-1)= (-p)(-1)

p= -5

Answer: p= -5

3 0

3 years ago