Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
Answer:
true
Step-by-step explanation:
Yes it is the same. 1/4 +1/4 = 1/2. so 9/10-1/2=9/10-1/2
The height of larger will be 3 cm
As,
= ∛8 cm³ * 27 cm³ / (2 cm) ³
= 3cm
Answer:
50%
Step-by-step explanation:
Actual value - estimated value
Actual value = 24 miles
Estimated value = 36 miles
Estimated value - Actual value
= 36 miles - 24 miles
= 12 miles
% error = change in value / actual value × 100
= 12/ 24 × 100
= 1/2 × 100
= 50%
% error = 50%