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antiseptic1488 [7]
3 years ago
10

Y = 2x x + y = −6 the answer should be like this (x,y) or ( , )

Mathematics
1 answer:
melisa1 [442]3 years ago
6 0

Answer:

(-2, -4)

Step-by-step explanation:

Given:

The system of equations to solve is given as:

y=2x\\\\x+y=-6

In order to solve this system of linear equations, we use substitution method.

In substitution method, we substitute the value of any one variable in the other equation.

So, we substitute the value of 'y' from first equation in the second equation.

This gives,

x+2x=-6\\\\3x=-6

Dividing both sides by 3, we get:

\frac{3x}{3}=\frac{-6}{3}\\\\x=-2

Now, y=2x=2\times -2=-4

Therefore, the solution is (-2, -4)

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These are two questions and two answers.

Question 1) Which of the following polar equations is equivalent to the parametric equations below? 

<span> x=t²
y=2t</span>

Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>

Explanation:

1) Polar coordinates ⇒ x = r cosθ and y = r sinθ

2) replace x and y in the parametric equations:

r cosθ = t²
r sinθ = 2t

3) work r sinθ = 2t

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5) simplify

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4 = r (sinθ)² / cos θ

r = 4 cosθ / (sinθ)²

r = 4 cot θ csc θ ↔ which is the option A.


Question 2) Which polar equation is equivalent to the parametric equations below?

<span> x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>

Answer: option B) r = sinθ + 1


Explanation:

1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ

2) replace x and y in the parametric equations:

a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span> b) r sinθ =sin²(θ)+sin(θ)</span>

3) work both equations

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<span> b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
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</span>Therefore, the answer is r = sinθ + 1 which is the option B.
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Answer:

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5 0
2 years ago
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Answer:

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_____

<em>Additional comment</em>

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