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qaws [65]
3 years ago
11

Harold wants to build five identical pigpens side by side on his farm using 30 m of fencing. Determine the dimensions of the enc

loser that would give his pigs the largest possible area. Calculate the area
Mathematics
2 answers:
Nadya [2.5K]3 years ago
6 0

Answer:

He would give his pigs 14.33 m2 area at most.

Step-by-step explanation:

If he wants to give to pigs the possible largest area, pigpens should be shaped as round. He need to use 6m of fence each to build 5 identical pigpens. And radius of each pigpen will be:

2*\pi *r=6\\r=3/\pi \\r=0.96

and the area of the each pigpen will be:

\pi *r^{2}=3.14*0.96^{2}  =2.87

2.87 m2 is the area of each pigpen. In total 14.33 m2 area pigs are gonna have.

lorasvet [3.4K]3 years ago
5 0

2x2 for each pen with four in a square and one to the side kind of like this

===                                                                                                                                       ==

each length of fencing would be 2 meters and the total square footage would be 20 meters because some of the fencing is used for more than one pig's pen

the dimensions would be hard to show, but 4x4+ a 2x2


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antiseptic1488 [7]

Answer:

The center of this circle is (5, -4) and the radius is 1.

Step-by-step explanation:

First regroup these terms according to x and y :

x^2 - 10x + y^2 + 8y = -40

Next, complete the square for x^2 - 10x:  x^2 - 10x + 5^2 - 5^2.

and the same for y^2 + 8y:  y^2 + 8y + 16 - 16

Substituting these results into x^2 - 10x + y^2 + 8y = -40, we get:

x^2 - 10x + 5^2 - 5^2 y^2 + 8y + 16 - 16 = -40.

Next, rewrite x^2 - 10x + 25 and y^2 + 8y + 16 as squares of binomials:

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(x - 5)^2 + (y + 4)^2 - 25 - 16 = -40, or:

(x - 5)^2 + (y + 4)^2 = 1

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The center of this circle is (5, -4) and the radius is 1.

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3 years ago
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Answer:

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Step-by-step explanation:

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