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vazorg [7]
3 years ago
8

If f(x) = 5x + 40, what is f(x) when x О-9 От o15 .

Mathematics
2 answers:
qaws [65]3 years ago
7 0

Answer: x = -9, x = 115

Step-by-step explanation:

when x = -9 :

5(-9) + 40

-45 + 40

= -5

when x = 15

5(15) + 40

75 + 40

= 115

Art [367]3 years ago
5 0

Answer:

X = -5, 40, 115

Step-by-step explanation:

when x = 0-9

5(0-9) + 40

-45 + 40

= -5

when x = 0T =0

5(0) + 40

0 + 40

= 40

when x = 015=15

5(15) + 40

75 + 40

= 115

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Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 3 at x = −3 and a local minimum value of 0 at
Amiraneli [1.4K]

Answer:

The cubic function is f(x) = (27/32)·x  - 3/32·x³ - -9/32·x² - 9/32

Step-by-step explanation:

The given function is f(x) = a·x³ + b·x² + c·x + d

By differentiation, we have;

3·a·x² + 2·b·x + c = 0

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-27·a + 9·b - 3·c + d = -3...(1)

a + b + c + d = 0...(2)

Subtracting equation (1) from equation (2) gives;

28·a - 8·b + 4·c = 3

Therefore, we have;

27·a - 6·b + c = 0

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28·a - 8·b + 4·c = 0

Solving the system of equations using an Wolfram Alpha gives;

a = -3/32, b = -9/32, c = 27/32 from which we have;

a + b + c + d = 0 3 × (-3/32) + 2 × (-9/32) + (27/32) + d = 0

d = 0 - (0 3 × (-3/32) + 2 × (-9/32) + (27/32)) = -9/32

The cubic function is therefore f(x) = (-3/32)·x³ + (-9/32)·x² + (27/32)·x + (-9/32).

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