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taurus [48]
2 years ago
11

fifteen percent of the 20 players on the soccer team are new this year how many players on the team are new this year

Mathematics
2 answers:
Mamont248 [21]2 years ago
6 0

Answer:

Its 3

Step-by-step explanation:


aksik [14]2 years ago
4 0
15% of 20 is 3. So 3 players are new this year.

:)
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The population of a town has approximately doubled every 17 years since 1950. If the equation P=Po2k, where Po is the population
natka813 [3]

The population of a town has approximately doubled every 17 years since 1950.

the equation P=P_02^k where Po is the population of the town in 1950, is used to model the population, P, of the town t years after 1950.

When t=17 yrs

   P=2p_{0}      

for 1 year

The equation becomes

P = P_02^\frac{t}{17}                               -------------(1)

Our original equation is

P=P_02^k----------------------------------(2)

equating expression 1  and 2

P_02^\frac{t}{17}=P_{0}2^k

Cancelling P_{0}  from both sides  we get

2^\frac{t}{17}=2^{k}

t/17=k

⇒k=t/17 is the solution.






4 0
2 years ago
At an animal park 2/5 of the animals are felines, and 1/4 of the animals are reptiles. The rest of the animals are aquatic. What
notka56 [123]

Answer:

Felines: 40%

Reptiles: 25%

Aquatic Animals is 35%

Which means the Answer is 35%

(How you do this)

- First, Divide, the Numerator, by the Denominator and multiply it by 100.

3 0
2 years ago
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Which points are a solution to the equation y = 5x - 4?
denis-greek [22]

Answer:

The answer are

(0,_4)

(2,6)

(3,11)

4 0
2 years ago
Write a number with the digit 8 in the tens place
koban [17]

80 is a good one to start with.

After that, you can move on to  83,  481,  1687, and  102,974,589 . 

6 0
3 years ago
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How to I solve problem 1?
Verdich [7]
#1

The uniforms are numbered 0, 1, 2, ..., 99. That's 100 numbers. Half of them are odd and half of them are even. So the probability that any one of the uniforms is odd is 1/2 just like the probability that any one uniform is even is 1/2.

(a) The numbers on the uniforms are independent of one another. That is, the number of her cross-country uniform does not in any way determine the number on her basketball uniform and vice versa. This means that we can find the probability that each is odd and multiply these together using what is called the counting principle. The probability that all are odd is:
(1/2)(1/2)(1/2)=1/8

(b) This is done the same way we did part (a). Since the probability of any one uniform being odd is the same as it being even (1/2), the answer here is the same: (1/2)(1/2)(1/2)=1/8

(c) This problem differs from that in (a) and (b). There is only one way for all three uniforms to be odd numbers: (odd, odd, odd) or all even (even, even, even). However, there are multiple ways for the uniforms to be two odd and one even. If the uniforms are listed in order: cross-country, basketball, softball we can get exactly one even in any of three ways:
even, odd, odd
odd, even, odd
odd, odd, even
The probability for any one of these possibilities is (1/2)(1/2)(1/2)=1/8 but since there are three way the probability that we get even exactly once is equal to (3)(1/8) = 3/8
7 0
2 years ago
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