Step-by-step explanation:
m∠3 = 7x - 10
m∠6 = 5x + 10
m∠3 = m∠6
7x - 10 = 5x + 10
7x - 5x = 10 + 10
2x = 20
x = 20/2 = 10°
Answer:
54
Step-by-step explanation:
Tn = an²+bn
T2 = a2²+2b
2 = 4a +2b
Multiply all through by 2
4 = 8a +4b
4b = 4-8a
T4 = a4² + 4b
20 = 16a +4b
4b = 20-16a
4-8a = 20-16a
16a -8a = 20-4
8a = 16
a = 16/8 = 2
4b = 4-8a = 4-8(2) = 4-16 = -12
b = -12/4 = -3
T6 = a6² + 6b
T6 = 2(36) + 6(-3) = 72 -18 = 54
To figure out if the ordered pairs are a solution to the equations, you would need to plug in the points. Your points are ordered as (x,y)
You would plug in the number that's in the x spot in x, and the number in the y spot in y.
Let's start of with the first problem:
First thing you would do is plug in (-1) to x, and 6 to y.
Your equations would look like this:
6(-1) + 3(6) = 18
2(-1) + 6 = 7
What you would now do is solve the equations. When you solve them, you would get these answers
12 = 18
4 = 7
For #1, it would be no solution because the numbers do not equal each other. (Fun fact) If one of them ends up as a solution, but the other is no solution, the answer would be no solutions because BOTH of them have to be a solution to the equations given in order to be a solution.
If you do the same strategy, (plugging in the numbers to x and y), you would get the rest of the answers for the problems.
I hope this helps, if you need any more assistance, I would be glad to help!
Answer:
s=13
Step-by-step explanation:
Answer: 
Step-by-step explanation:
By definition, a relation is a function if and only if each input value has one and only one output value.
For this exercise it is important to remember that thw "Input values" are the values of the variable "x"and the "Output values" are the values of the variable"y".
In this case you have the following function provided in the exercise:
Then, to solve this exercise, you need to follow these steps:
Step 1. You have to substitute 
into the function given.
Step 2. Finally, you must evaluate in order to find the corresponding output value (or the value of the variable "y")
You get that this is:
