What is the equation for a quadratic function

marta [7]

-3 • (5x + 2y = 7)
-15x - 6y = -21
-2x + 6y = 9
__________
-17x = -12
x = 12/17
5(12/17) + 2y = 7
2y = 7 - 60/17
2y = 3.47
y = 1.735

3 0

2 years ago

Read 2 more answers

What is the length of the missing leg?

Dmitry [639]

Answer: b = 8

Step-by-step explanation:

Use the Pythagorean theorem

A square + B square = C square

C square - A square = B square

C square - B square = A square

10 - 6 = b --Square it

100 - 36 = 64 (square root)

64 = 8

b = 8 miles

7 0

2 years ago

A piece of paper is cut and then folded into rectangular prism as shown below.

CaHeK987 [17]

A. C is on the bottom, Bis on the left

5 0

3 years ago

Can someone help me with this

SashulF [63]

Answer:

$\angle NRQ =85 \degree$

Given:

$\angle RPQ = 45 \degree \\ \angle PQR = (6x + 4)\degree \\ \angle NRQ = (15x - 5)\degree$

Step-by-step explanation:

Property used: An exterior angle of a triangle is equal to the sum of the opposite interior angles.

$= > \angle RPQ + \angle PQR = \angle NRQ \\ \\ = > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\ \\ = > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\ \\ = > 49\degree + 5 \degree= 15x\degree - 6x\degree \\ \\ = > 54\degree = 9x\degree \\ \\ = > 9x\degree = 54\degree \\ \\ = > x\degree = (\frac{54}{9} )\degree \\ \\ = > x\degree = 6\degree \\ \\ Putting \: value \: of \: x \: in \: \angle NRQ \\ \\ = > \angle NRQ = (15x - 5)\degree \\ \\ = > \angle NRQ = (15 \times 6 - 5) \degree \\ \\ = > \angle NRQ =85 \degree$

4 0

2 years ago

PLEASE HELP ITS EXTRA CREDIT AND I COULD REALLY USE IT !! BEING TIMED! for each of the following statements, determine if the st

bogdanovich [222]

A. True. We see this by taking the highest order term in each factor:

$f(x) = -3x(x-5)^3(x+2)^2 = -3x (x^3 + \cdots) (x^2 + \cdots) = -3x^{\boxed{6}} + \cdots$

B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.

C. False. f(x) = 0 only for x=0, x = 5, and x = -2.

D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.

E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).

F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.

8 0

1 year ago