Answer:
HOPE THIS HELPS
Step-by-step explanation:
The area = length * Width.
We know the width = X+6 inches and Area = x^3+3x^2–18x.
This problem can be solved just by dividing the area by width and we get a quotient as X^2–3x.
So the length is x^2–3x inches.
Answer:
119
Step-by-step explanation:
Divided by x and y for total engagement of relationship between two beings of equation.
Answer: The seasonal relatives is calculated are as follows:
Step-by-step explanation:
Given that,
restaurant only open from Wednesday to Saturday,
- 29 percent of its business on Friday
- 31 percent on Saturday night
- 21 percent on Thursday night.
∴ The remaining 19% of its business he does on Wednesday
Now, suppose that total production of sales in a given week be 'y'
So, average sales in a week = ![\frac{y}{4}](https://tex.z-dn.net/?f=%5Cfrac%7By%7D%7B4%7D)
If we assume that y = 1
hence, average sales in a week = ![\frac{1}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D)
= 0.25
Now, we have to calculate the seasonal relatives,
that is,
= ![\frac{Sales in a given day}{average sales in a week}](https://tex.z-dn.net/?f=%5Cfrac%7BSales%20in%20a%20given%20day%7D%7Baverage%20sales%20in%20a%20week%7D)
Wednesday:
= ![\frac{0.19}{0.25}](https://tex.z-dn.net/?f=%5Cfrac%7B0.19%7D%7B0.25%7D)
= 0.76
Thursday:
= ![\frac{0.21}{0.25}](https://tex.z-dn.net/?f=%5Cfrac%7B0.21%7D%7B0.25%7D)
= 0.84
Friday:
= ![\frac{0.29}{0.25}](https://tex.z-dn.net/?f=%5Cfrac%7B0.29%7D%7B0.25%7D)
= 1.16
Saturday:
= ![\frac{0.31}{0.25}](https://tex.z-dn.net/?f=%5Cfrac%7B0.31%7D%7B0.25%7D)
= 1.24
Answer:
The answers are as follows:
5. c
6. b
7. not sure, sorry
8. b
Step-by-step explanation:
In the data shown, rearranging the data [<span>9.4, 9.2, 9.7, 9.8, 9.4, 9.7, 9.6, 9.3, 9.2, 9.1, 9.4] from the least to the greatest would give us the following data set:
9.1, 9.2, 9.2, 9.3, 9.4, 9.4, 9.4, 9.6, 9.7, 9.7, 9.8
The box-plots uses a 5-number summary. The minimum value, then Q1 which is the media of the lower half of the set, Q2 which is the median of the total set, Q3 which is the median of the upper half of the set, and Q4 which is the highest number. Among the choices, the correct answer is B.</span>