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3 years ago

12

These are the times for five runners in 5k race. javel 35minutes , Tarone 39 minutes, Grace 42 minutes, Margaret 45 minutes, Zig

gy 32 minutes. which runner took the second longest time?

1 answer:

Rus_ich [418]3 years ago

7 0

Answer:

grace

...................

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What expressions are equivalent to 7^3 * 7^x

solong [7]

Answer:

The question = (7^3)*(7^x)

When multiplying two exponents with the same base, all you do is add the exponents together and keep the same base

Therefore,

(7^3)*(7^x) = 7^(3+x)

Step-by-step explanation:

7^3+x is the answer

3 0

3 years ago

Please answer this question now

shusha [124]

Hi there! :)

Answer:

$\huge\boxed{V = 359.01 mm^{3} }$

Use the formula V = 1/3(bh) to solve for the volume of the cone where b = πr² where π ≈ 3.14:

Find the area of the base:

b = π(7)²

b = 49π

b = 153.86 mm²

Find the volume:

V = 1/3(153.86 · 7)

V = 1/3(1077.02)

V = 359.006 ≈ 359.01 mm³.

4 0

3 years ago

A laptop computer sells for $850. the sales tax is 7%. what is the total cost of the laptop?

evablogger [386]

Answer:

$909.50

Step-by-step explanation:

$850 x 7% = $59.50 (tax amount)

850 x (1+ 0.07) = $909.50

4 0

3 years ago

Explain how you know which coins could be used to show 0.77 of a dollar

Illusion [34]

you can use 3 quarters and 2 pennies

8 0

3 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by <em>b</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since <em>a/b</em> < <em>c/d</em>, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by <em>b/d</em> to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and <em>a/b</em> < <em>c/d</em> tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

5 0

3 years ago