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4 years ago

7

The nutritional information on Xuan’s container of crackers said that it had 162 calories. If there were 24 crackers in the cont

ainer, which best describes the number of calories in each cracker?
a.approximately 6 calories
b.approximately 7 calories
c.approximately 13 calories
d.approximately 14 calories

2 answers:

frez [133]4 years ago

7 0

Answer:

The number of calories in each cracker is approximately 7 calories .

Option (b) is correct .

Step-by-step explanation:

As given

The nutritional information on Xuan’s container of crackers said that it had 162 calories.

If there were 24 crackers in the container.

$The\ number\ of\ calories\ in\ each\ crackers = \frac{162}{24}$

The number of calories in each cracker = 6.75

(6.75 is approximately written as 7)

Thus the number of calories in each cracker is approximately 7 calories.

zmey [24]4 years ago

4 0

Answer:

B (approximately 7 calories.

Step-by-step explanation: I took the quiz & got an 100% :)

good luck! hope I could help <3

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Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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3 years ago

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Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

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the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

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$d=\sqrt{(-24)^{2}+(7)^{2}}$

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B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

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we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

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A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

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substitute the given values

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Answer:

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Step-by-step explanation:

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