Answer:
Step-by-step explanation:
Given equation can be re written as
............(i)
Now it is given that y(π/2) = 2e
Applying value in (i) we get
ln(2e) = sin(π/2) + c
=> ln(2) + ln(e) = 1+c
=> ln(2) + 1 = 1 + c
=> c = ln(2)
Thus equation (i) becomes
ln(y) = sin(x) + ln(2)
ln(y) - ln(2) = sin(x)
ln(y/2) = sin(x)
If his 1st stroke went 4/5 of the way to the hole, that means the 2nd stroke was 1/5 of the distance. Since we know that the 2nd stroke was 79 meters, we can use this to find the distance from where he started...
If 1/5 = 79 meters then
4/5 = 79 × 4 = 316 meters
Since 1/5 + 4/5 = 5/5 = 1 then 79 m + 316 m = 395 meters for the total distance.
But wait! There's more. The question asks how many kilometers the hole is from where he started... there are 1000 meters per kilometer so...
395 m × 1 km/1000 m =
395/1000 m = .395 km
Total distance from start to hole is .395 km
Yay!!
Answer:
c. (A + B)^2-A^2 + 2AB + B^2
Step-by-step explanation:
Given that:
a.
(A-B)^2 = A^2 - 2AB + B^2
If and only if AB = BA
Then;
(A-B)^2 = (A -B ) (A - B)
(A-B)^2 = A^2 - AB-BA + B^2 (FALSE)
b.
(AB)^2=A^2B^2
on true if any only if AB =BA
(AB)^2= (AB) (AB)
c.
(A+ B)^2 = A^2 + 2AB + B^2
(A+ B)^2 = (A + B) (A+B)
(A+ B)² = A × A + A × B + B × A + B × B
(A+ B)^2 = A^2 + A*B + B*A + B^2
This is true
