Brainly + 30 points!<br>Find the values of a, b, and c

Select the correct answer.

Rama09 [41]

Answer:

it's d

Step-by-step explanation:

3 0

2 years ago

Chef Andy needed to adapt his recipes for his European kitchen staff in Paris. He was 1-pound portions of entrecote, 2 ounces

Ronch [10]

Answer:

1 pound = 0.454 kilograms

1 ounce = 0.0296 liters

1 ounce = 0.0283 kilograms

Step-by-step explanation:

You need to convert the quantities to their corresponding unit.

Convert pounds to kilograms (For the entrecote)

1 pound = 0.454 kilograms

Thus, 1 pound of entrecote = 0.454 kilograms

Ounces to liters (for the Béarnaise, since it is a liquid)

1 ounce = 0.0296 liters

2 ounces of Béarnaise = 0.0592 liters

Ounces to kilograms (for the asparagus)

1 ounce = 0.0283 kilograms

4 ounces of asparagus =0.1132 kilograms

8 0

3 years ago

First pirson to type 1 i will see if i can give brainlist but idk how bot i will try

amm1812

Answer:

1

Step-by-step explanation:

you asked to type 1

3 0

2 years ago

Task 1 Nonlinear Systems of Equations Create a system of equations that includes one linear equation and one quadratic equation.

Luden [163]

Answer:

hope this helps

Step-by-step explanation:

solution:

x^2 + 3x + 5 = x + 13

x^2 + 2x -8 = 0

(x+4)(x-2) = 0

x = -4 or x = 2

if x = -4, y = 9

if x = 2 , y = 15

4 0

3 years ago

A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an a

Scrat [10]

Answer:

The answer is (C) 8

Step-by-step explanation:

First, let's calculate the length of the side of the square.

$A_{square}=a^2$ , where $a$ is the length of the side. Now, let's try to build the square. First we need to find a point which distance from (0, 0) is 10. For this, we can use the distance formula in the plane:

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$ which for $x_1=0$ and $y_1 = 0$ transforms as $d=\sqrt{(x_2)^2 + (y_2)^2}$ . The first point we are looking for is connected to the origin and therefore, its components will form a right triangle in which, the Pythagoras theorem holds, see the first attached figure. Then, $x_2$ , $y_2$ and 10 are a Pythagorean triple. From this, $x_2= 6$ or $x_2=8$ while $y_2= 6$ or $y_2=8$ . This leads us with the set of coordinates:

$(\pm 6, \pm 8)$ and $(\pm 8, \pm 6)$ . (A)

The next step is to find the coordinates of points that lie on lines which are perpendicular to the lines that joins the origin of the coordinate system with the set of points given in (A):

Let's do this for the point (6, 8).

The equation of the line that join the point (6, 8) with the origin (0, 0) has the equation $y = mx +n$ , however, we only need to find its slope in order to find a perpendicular line to it. Thus,

$m = \frac{y_2-y_1}{x_2-x_1} \\m = \frac{8-0}{6-0} \\m = 8/6$

Then, a perpendicular line has an slope $m_{\bot} = -\frac{1}{m} = -\frac{6}{8}$ (perpendicularity condition of two lines). With the equation of the slope of the perpendicular line and the given point (6, 8), together with the equation of the distance we can form a system of equations to find the coordinates of two points that lie on this perpendicular line.

$m_{\bot}=\frac{6}{8} = \frac{8-y}{6-x}\\ 6(6-x)+8(8-y)=0$ (1)

$d^2 = \sqrt{(y_o-y)^2+(x_o-x)^2} \\(10)^2=\sqrt{(8-y)^2+(6-x)^2}\\100 = \sqrt{(8-y)^2+(6-x)^2}$ (2)

This system has solutions in the coordinates (-2, 14) and (14, 2). Until here, we have three vertices of the square. Let's now find the fourth one in the same way we found the third one using the point (14,2). A line perpendicular to the line that joins the point (6, 8) and (14, 2) has an slope $m = 8/6$ based on the perpendicularity condition. Thus, we can form the system:

$\frac{8}{6} =\frac{2-y}{14-x} \\8(14-x) - 6(2-y) = 0$ (1)

$100 = \sqrt{(14-x)^2+(2-y)^2}$ (2)

with solution the coordinates (8, -6) and (20, 10). If you draw a line joining the coordinates (0, 0), (6, 8), (14, 2) and (8, -6) you will get one of the squares that fulfill the conditions of the problem. By repeating this process with the coordinates in (A), the following squares are found:

(0, 0), (6, 8), (14, 2), (8, -6)

(0, 0), (8, 6), (14, -2), (6, -8)
(0, 0), (-6, 8), (-14, 2), (-8, -6)
(0, 0), (-8, 6), (-14, -2), (-6, -8)

Now, notice that the equation of distance between the two points separated a distance of 10 has the trivial solution $(\pm10, 0)$ and $(0, \pm10)$ . By combining this points we get the following squares:

(0, 0), (10, 0), (10, 10), (0, 10)
(0, 0), (0, 10), (-10, 10), (-10, 0)
(0, 0), (-10, 0), (-10, -10), (0, -10)
(0, 0), (0, -10), (-10, -10), (10, 0)

See the attached second attached figure. Therefore, 8 squares can be drawn

8 0

2 years ago

Brainly + 30 points!Find the values of a, b, and c​

Brainly + 30 points!Find the values of a, b, and c