Question

At a local college, of the male students are smokers and are non-smokers. Of the female students, are smokers and are non-smokers. A male student and a female student from the college are randomly selected for a survey. What is the probability that both are non-smokers?

Answer 1

Answer: Our required probability is 0.88.

Step-by-step explanation:

Since we have given that

Number of male students are smokers = 10

Number of male students are non smokers = 490

total number of male students = 500

Number of female students are smokers = 40

Number of female students are non smokers = 363

Total number of female students = 403

Probability that both are non smokers is given by

$P(Non-smoker\ male)\times P(Non-smoker\ female)\\\\=\dfrac{490}{500}\times \dfrac{363}{403}\\\\=0.98\times 0.9\\\\=0.88$

Hence, our required probability is 0.88.