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brilliants [131]
2 years ago
8

If you are using algebra tiles to factor a trinomial of the form ax2 + bx + c, when would you need to bring in zero pairs? Why?

ANSWER ASAP ON EDGE
Mathematics
2 answers:
DochEvi [55]2 years ago
7 0
Is there a diagram. (Question mark)....
Ierofanga [76]2 years ago
4 0

Answer:

*Sample Response:* If the value of c is negative, you would need zero pairs to model the factorization of the polynomial. The x-tiles on the board determine what the constants are in the factors. The product of these constants is equal to the value of c, so you would need positive tiles on one side of the x-squared tile and negative x-tiles on the other side to have opposite signs on the constants. Opposite signs on the constants will result in a negative value for c when multiplying the factors.

Step-by-step explanation:

Its the sample response i dont know what explanation you need other than that.

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Step-by-step explanation:

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Find the value of x in the triangle shown below.
kobusy [5.1K]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Solve and find X. <br> Question says 5-x / 2 = 2x-7
poizon [28]

Answer:

x = 3.8

Step-by-step explanation:

The equation is (5 - x) / 2 = 2x - 7

Multiply both sides by 2:

5 - x = 4x - 14

Add 14 to both sides:

19 - x = 4x

Add x to both sides:

19 = 5x

Divide both sides by 5 to isolate x:

3.8 = x

Therefore, x = 3.8.

7 0
3 years ago
Read 2 more answers
The equation of a parabola is given.y=1/8x^2+4x+20 What are the coordinates of the focus of the parabola?
Lena [83]
He equation of a parabola is x = -4(y-1)^2. What is the equation of the directrix? 
<span>You may write the equation as </span>
<span>(y-1)^2 = (1) (x+4) </span>
<span>(y-k)^2 = 4p(x-h), where (h,k) is the vertex </span>
<span>4p=1 </span>
<span>p=1/4 </span>
<span>k=1 </span>
<span>h=-4 </span>

<span>The directrix is a vertical line x= h-p </span>
<span>x = -4-1/4 </span>
<span>x=-17/4 </span>

<span>------------------------------- </span>
<span>What is the focal length of the parabola with equation y - 4 = 1/8x^2 </span>
<span>(x-0)^2 = 8(y-4) </span>
<span>The vertex is (0,4) </span>
<span>4p=8 </span>
<span>p=2 (focal length) -- distance between vertex and the focus </span>
<span>------------------------------- </span>
<span>(y-0)^2 = (4/3) (x-7) </span>
<span>vertex = (7,0) </span>
<span>4p=4/3 </span>
<span>p=1/3 </span>
<span>focus : (h+p,k) </span>
<span>(7+1/3, 0)</span>
8 0
3 years ago
Read 2 more answers
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