All categories

3 years ago

Identify the value of x that makes each pair of ratios equivalent. 2:x and 12:18

Mathematics

1 answer:

m_a_m_a [10]3 years ago

7 0

Given:

Two ratios 2:x and 12:18 are equivalent.

To find:

The value of x.

Solution:

We have,

$2:x\equiv 12:18$

It means,

$\dfrac{2}{x}=\dfrac{12}{18}$

$2\times 18=12\times x$

$36=12x$

Divide both sides by 12.

$\dfrac{36}{12}=\dfrac{12x}{12}$

$3=x$

Therefore, the value of x is 3.

You might be interested in

To make 5 pizzas, 1/2 cup of flour is used a. How much flour is needed to make one pizza? b.. How many cups of flour are needed

pogonyaev

Answer:

for a single pizza 1/10 a cup

for 12 pizzas 1 1/5 a cup

you can make 56 pizzas with 5 2/3 cups.

Step-by-step explanation:

for 5 pizzas you need 1/2 cup of flour, so to find out how much you'll need for a single pizza you'll need to divide it with 5. 1/2÷5=1/10

for a dozen pizzas you'll need to multiply that with 12. 1/10x12=12/10=1 1/5

Then to find out how many can we make with 5 2/3 cups we'll divide it with that 1/10

56/10÷1/10= 56 pizzas

8 0

3 years ago

when they said went to bed the outside temperature was 28 degrees Fahrenheit when you woke up the next morning the temperature h

Ghella [55]

Answer:

41 degrees

Step-by-step explanation:

just subtract

7 0

3 years ago

(a) find the general solution to y^{\,\prime\prime} + 3 y^{\,\prime} = 0. give your answer as y = . . . \ . in your answer, use

KengaRu [80]

We want to solve
y'' + 3y' = 0

Solve the indicial equation.
m² + 3m = 0
m(m + 3) = 0
m = 0 or m = -3

The basic solutions are e⁰=1 and $e^{-3x}$ .

Answer:
The general solution is
$y(x) = c_{1} + c_{2}e^{-3x}$

4 0

3 years ago

2/3x +4 = 2/5 rewrite the equation so it doesn’t have fractions. Do not use decimals.

erma4kov [3.2K]

Answer:

exfv

Step-by-step explanation:

6 0

3 years ago

g A population is infected with a certain infectious disease. It is known that 95% of the population has not contracted the dise

trasher [3.6K]

Answer:

There is approximately 17% chance of a person not having a disease if he or she has tested positive.

Step-by-step explanation:

Denote the events as follows:

D = a person has contracted the disease.

+ = a person tests positive

- = a person tests negative

The information provided is:

$P(D^{c})=0.95\\P(+|D) = 0.98\\P(+|D^{c})=0.01$

Compute the missing probabilities as follows:

$P(D) = 1- P(D^{c})=1-0.95=0.05\\\\P(-|D)=1-P(+|D)=1-0.98=0.02\\\\P(-|D^{c})=1-P(+|D^{c})=1-0.01=0.99$

The Bayes' theorem states that the conditional probability of an event, say A provided that another event B has already occurred is:

$P(A|B)=\frac{P(B|A)P(A)}{P(B|A)P(A)+P(B|A^{c})P(A^{c})}$

Compute the probability that a random selected person does not have the infection if he or she has tested positive as follows:

$P(D^{c}|+)=\frac{P(+|D^{c})P(D^{c})}{P(+|D^{c})P(D^{c})+P(+|D)P(D)}$

$=\frac{(0.01\times 0.95)}{(0.01\times 0.95)+(0.98\times 0.05)}\\\\=\frac{0.0095}{0.0095+0.0475}\\\\=0.1666667\\\\\approx 0.1667$

So, there is approximately 17% chance of a person not having a disease if he or she has tested positive.

As the false negative rate of the test is 1%, this probability is not unusual considering the huge number of test done.

7 0

3 years ago