Attached the conversion and solution. You would normally divide to convert but with the unit being cube we have to divide by the conversion cubed. So for dm to m we would just divide by 10 but the cube changes everything so you would divide by 10^3. Same with the rest.
what i would do is implant some number under 5 for the X's.
Then work it out as if 3 was x so for instance -4(8-3x3)
Answer:
The sum of the first five classroom numbers in a row is 5k + 20
Step-by-step explanation:
Since the smallest classroom number on the side of the building is numbered k and each consecutive odd integer is separated by a difference of
2.
Therefore:
k is the first class room.
k + 2 is the second class room.
k + 4 is the third class room.
k + 6 is the third class room.
k + 8 is the fifth class room.
The sum of the five consecutive class rooms are given as:
k + (k + 2) + (k + 4) + (k + 6) + (k + 8)
collecting alike terms we get
= k + k + k + k + k + 2 + 4 + 6 + 8
= 5k + 20
Therefore, The sum of the first five classroom numbers in a row is 5k + 20.
keep trying good luck to you
Y=-5x-7. I'm almost certain but you never know
