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cricket20 [7]
3 years ago
5

25÷1575 how many times can 25 go into 157?

Mathematics
2 answers:
g100num [7]3 years ago
8 0
That answer is 0.0158
Monica [59]3 years ago
7 0
The answer for 25 divided by 25 is 63.
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3.467 rounded to the nearest tenth of an ounce
kicyunya [14]

The 4 is in the tenth place...so you have to look at the number beside it to see if you round up or down. It's a 6, which is greater than 5 so you round up.

3.5

6 0
3 years ago
Mario paid $44.25 in taxi fare from the hotel to the airport. the cab charged $2.25 for the first mile plus $3.50 for each addit
natali 33 [55]
44.25 - 2.25 = 42.
42/3.50 = 12

12 + 1 = 13 miles
5 0
2 years ago
PLEASE EXPLAIN BECAUSE A GIRL IS COMPLETELY LOST HERE
Afina-wow [57]

Hello!


To find the value of b, we need to use the Law of Sines. The law states,

sin A / a = sin B / b = sin C / c.


We are given these values: sin A = 55 degrees, side a = 8 cm, sin C = 82 degrees.


Since angle B is not given, we have to find it ourselves. We can find the measure of angle B by subtracting both the given angle values from 180 degrees because every triangle is equal to 180 degrees.


180 - 55 - 82 = 43 | The measure of sin B = 43 degrees.


sin (55) / 8 = sin (43) / b (multiply both sides by b)

0.10239... · b = 0.68199... (divide both sides by 0.10239...)

c = 6.6607...


The measure of side b is equal to about 6.7 centimeters.

3 0
3 years ago
Read 2 more answers
Three times a number is at most negative six.<br> 3x5-6<br> O 3x2-6<br> O 3x&lt;-6<br> O 3x&gt;-6
geniusboy [140]
The answer is 9 because you solve it from left to right and 3x5 equals 15, 15 subtracted by 6 equals 9
6 0
3 years ago
Read 2 more answers
Let II be the tangent plane to the graph of f(x, y) = 8 – 2x^2 – 3y^2 at the point (1, 2,-6). Let S, x² + y^2 + z = 4 be another
stealth61 [152]

Let F(x,y,z)=f(x,y)-z. The tangent plane to f(x,y) at (1, 2, -6) has equation

\nabla F(1,2,-6)\cdot(x-1,y-2,z+6)=0

We have

\nabla F(x,y,z)=(-4x,-6y,-1)\implies\nabla F(1,2,-6)=(-4,-12,-1)

Then the tangent plane has equation

(-4,-12,-1)\cdot(x-1,y-2,z+6)=0\implies -4(x-1)-12(y-2)-(z+6)=0\implies 4x+12y+z=22

Let g(x,y)=4-x^2-y^2, and G(x,y,z)=g(x,y)-z. The tangent plane to S at a point (a,b,c) is

\nabla G(a,b,c)\cdot(x-a,y-b,z-c)=0

We have

\nabla G(x,y,z)=(-2x,-2y,-1)\implies \nabla G(a,b,c)=(-2a,-2b,-1)

so that this plane has equation

(-2a,-2b,-1)\cdot(x-a,y-b,z-c)=0\implies2ax+2by+z=2a^2+2b^2+c

In order for this plane to be parallel to the previous plane, we need to have

\begin{cases}2a=4\\2b=12\end{cases}\implies a=2,b=6\implies g(a,b)=c=-36

so the point we're looking for is (2, 6, -36).

6 0
3 years ago
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